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maw [93]
3 years ago
14

The least-squares regression line is: Group of answer choices a. the line that passes through the most data points. b. the line

that minimizes the sum of the squares of the vertical distances from each point to the line. c. the line such that half of the data points fall above the line and half fall below the line d. all of the above are correct
Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

Answer:

a. the line that passes through the most data points.

Step-by-step explanation:

The least-squares regression line is the line that passes from mostly all the data points also this line would be located on a scatterplot that minimizes the distance square from the points to the line

Therefore as per the given situation, the option a is correct

Hence, the rest of the given options would be wrong

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Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
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Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

  • Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171,  Z = (4171 - 3311)/860 = 1  

  • P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

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The owner of a fish market has an assistant who has determined that the weights of catfish are normally​ distributed, with mean
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Answer:

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#First determine the z-value:

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#We then determine the corresponding probability on the z tables:

Z(X\geq 3.4)=1-P(X

Hence, the probability of obtaining a sample mean this large or​ larger is 0.0228

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