Find the area of the figure

Find the price-demand equation for a particular brand television when the demand is 20 TVs per week at $150 per TV, given that t

Alina [70]

Answer:

~ $150=50e^{-0.01()20}$

~ $p(100)=\$127.7$

Step-by-step explanation:

From the question we are told that:

Price of 20TVs per week $P_{20}=\$150$

Marginal price-demand function $p'(x)=-0.5e-0.01x$

Generally the The Marginal price function is mathematically given by

$p'(x)=-0.5e^{-0.01x}$

$p(x)=\int-0.5e^{-0.01x}$

$p(x)=50e^{-0.001x}+C$

Therefore the equation when the demand is 20 TVs per week at $150 per TV

$150=50e^{-0.01()20}$

Giving

$p(x)=50e^{-0.01x}+150-50e^{-0.01(20)}$

Therefore the Price when the demand is 100 TVs per week

$p(100)=50e^{-0.01(100)}+150-50e^{-0.01(20)}$

$p(100)=\$127.7$

7 0

2 years ago

What is the interest for a principal of $3,500 at a simple interest rate of

Zielflug [23.3K]

Answer:

hi hope it helps

I=$336

Step-by-step explanation:

P=$3500, R=3.2%, T=3yrs and I=?

I=PRT/100

=3500x3.2x3/100

=33600/100

=$336

5 0

2 years ago

Please help with math!

svet-max [94.6K]

You're going to have to reupload it, I'm sorry! Only have of the question shows!

5 0

2 years ago

Pls help. i never understood this rule.

Dimas [21]

L'Hopital rule only applies to indeterminate cases of 0/0 or ∞/∞ or 0*0 or ∞ * ∞.

and you'd need to make the expression a rational, where the numerator and denominator gives you 0/0 or ∞/∞, then you apply L'Hopital.

the only candidate there is

$\bf \lim\limits_{x\to \infty}\cfrac{2x^2-1}{3x+1}\implies \lim\limits_{x\to \infty}\cfrac{2(\infty)^2-1}{3(\infty)+1}\implies \cfrac{\infty}{\infty}
\\\\\\
\textit{so we can use L'Hopital by instead using the derivatives}
\\\\\\
\lim\limits_{x\to \infty}\cfrac{2x^2-1}{3x+1}\stackrel{LH}{\implies }\lim\limits_{x\to \infty}\cfrac{4x}{3}\implies \cfrac{4(\infty)}{3}\implies \infty$

8 0

3 years ago

URGENT!!! What happens to the graph of y=−x6−6x5+50x3+45x2−108x−108 as x heads toward ∞ and −∞?

mr Goodwill [35]

Using limits, the correct option regarding the end behavior of the function is given by:

A. as x→∞, y→−∞ as x→−∞, y→−∞.

<h3>How to find the end behavior of a function f(x)?</h3>

The end behavior is found calculating the limit of f(x) as x goes to infinity.

For this problem, the equation is given by:

$f(x) = -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108$

Since x goes to infinity, we consider only the term with the highest exponent, hence the limits are given as follows:

$\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow -\infty} -x^6 = -(-\infty)^6 = -\infty$

$\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow \infty} -x^6 = -(\infty)^6 = -\infty$

Hence the correct option is:

A. as x→∞, y→−∞ as x→−∞, y→−∞.

More can be learned about limits and end behavior at brainly.com/question/22026723

#SPJ1

3 0

1 year ago