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3 years ago

May I please get the answers to the first 4 of these problems?

Mathematics

1 answer:

Ugo [173]3 years ago

7 0

Given:
A(3,0)
B(1,-2)
C(3,-5)
D(7,-1)

1) reflect across x=-4
essentially calculate the difference between the x=-4 line and Px and "add" it in the other direction to x=-4
A(-4-(3-(-4)),0)=A(-11,0)
B(-4-(1-(-4)),-2)=B(-9,-2)
C(-4-(3-(-4),-5))=C(11,-5)
D(-4-(7-(-4)),-1)=D(-15,-1)

2) translate (x,y)->(x-6,y+8)
A(-3,8)
B(-5,6)
C(-3,3)
D(1,7)

3) clockwise 90° rotation around (0,0), flip the x&y coordinates and then decide the signs they should have based on the quadrant they should be in
A(0,-3)
B(-2,-1)
C(-5,-3)
D(-1,-7)

D) Dilation at (0,0) with scale 2/3, essentially multiply all coordinates with the scale, the simple case of dilation, because the center point is at the origin (0,0)
A((2/3)*3,(2/3)*0)=A(2,0)
B((2/3)*1,(2/3)*-2)=B(2/3,-4/3)
C((2/3)*3,(2/3)*-5)=C(2,-10/3)
D((2/3)*7,(2/3)*-1)=D(14/3,-2/3)

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Hello, I know it is kinda late but here's a question.

zaharov [31]

The solution of the linear equation is a = 11/4.

<h3></h3><h3>How to solve the linear equation?</h3>

Here we have the linear equation:

9 = 4a - 2

We want to solve this for a, so we need to isolate a on one side of the equation.

First, we can add 2 on both sides to get:

9 + 2 = 4a

11 = 4a

Now we can divide both sides by 4 to get:

11/4 = a

The solution of the linear equation is a = 11/4.

If you want to learn more about linear equations:

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8 0

2 years ago

2/5 kg of soul fills 1/3 of a container so 1 kg of sulfate in the container? Explain or show your reasoning

Softa [21]

Answer:

Yes, we can put 1 kg of the soul in the container.

Step-by-step explanation:

Consider the provided information.

2/5 kg of soul fills 1/3 of a container.

It means if we put 2/5 kg of the soul 3 times in the container then the container will be full.

$\frac{2}{5}+\frac{2}{5}+\frac{2}{5}=\frac{6}{5}$

It means $\frac{6}{5}$ kgs of soul fill the container.

$\frac{6}{5}$ is greater than 1 so it means we can put 1 kg of the soul in the container.

6 0

3 years ago

4. a) Which method can be used to prove the triangles congruent?

Marina86 [1]

They are congruent by SSS

triangle ANP is congruent to triangle LCK is one of several possibilities for question B

3 0

3 years ago

Find the sixth term of the sequence 1/2, -3/8, 9/32

sukhopar [10]

Answer:

The sixth term is -243/2048 ⇒ answer B

Step-by-step explanation:

* Lets explain the geometric sequence

- There is a constant ratio between each two consecutive numbers

- Ex:

# 5 , 10 , 20 , 40 , 80 , ………………………. (×2)

# 5000 , 1000 , 200 , 40 , …………………………(÷5)

* General term (nth term) of a Geometric sequence:

# U1 = a , U2 = ar , U3 = ar² , U4 = ar³ , U5 = ar^4

# Un = ar^(n-1), where a is the first term , r is the constant ratio

between each two consecutive terms and n is the position of the

number in the sequence

- Ex: U5 = ar^4 , U7 = ar^6 , U10 = ar^9 , U12 = ar^11

- Lets solve the problem

∵ The sequence is 1/2 , -3/8 , 9/32

- Lets find the constant ratio r

∵ The first term is a = 1/2

∵ The second term is U2 = ar

∵ The second term U2 = -3/8

∴ ar = -3/8

∴ 1/2 r = -3/8 ⇒ multiply both sides by 2

∴ r = -3/4

- Lets find the sixth term

∵ a = 1/2 and r = -3/4

∵ n = 6

∴ U6 = ar^5

∴ U6 = 1/2 (-3/4)^5 = 1/2 × -243/1024 = -243/2048

* The sixth term is -243/2048

8 0

3 years ago

Read 2 more answers

If x – 10 is a factor of x2 – 8x – 20, what is the other factor?

Svetach [21]

Answer:

The other factor is $(x+2)$

Step-by-step explanation:

we know that

$(x-a)(x-b)=x^{2}-xb-xa+ab$

$(x-a)(x-b)=x^{2}-(a+b)x+ab$

In this problem we have

$x^{2} -8x-20$

and

$a=10$ -----> because is a factor

substitute and solve for b

$x^{2} -8x-20=x^{2}-(10+b)x+10b$

$8=10+b\\b=-2$

Verify in the second equation

$-20=10b$ -----> $-20=10(-2)$ -----> $-20=-20$ --> is ok

The other factor is $(x+2)$

3 0

3 years ago

Read 2 more answers