Answer:
10 losses
Step-by-step explanation:
Here, we want to get the greatest possible number of games the team lost
Let the number of games won be x
Number drawn be y
Number lost be z
Mathematically;
x + y + z = 38
Let’s now work with the points
3(x) + 1(y) + z(0) = 80
3x + y = 80
So we have two equations here;
x + y + z = 80
3x + y = 80
The greatest possible number of games lost will minimize both the number of games won and the number of games drawn
We can have the following possible combinations of draws and wins;
26-2
25-5
24-8
23-11
22-14
21-17
21-17 is the highest possible to give a loss of zero
Subtracting each sum from 38, we have the following loses:
10, 8, 6, 4, 2 and 0
This shows the greatest possible number of games lost is 10
Answer:
The answer to number 1 is geometric sequence of A>
Step-by-step explanation:
You would divide 6 by 30.
6/30=0.2
Therefore the answer is D
Answer:
3.4
Step-by-step explanation:
If we look at the top left triangle and the triangle with x, we notice that they are similar (since they have a 57° and a right angle). This means that 4 / 1 = x / 0.84, which means that x = 3.4.
Answer:
x= 17+7y/15 as a fraction
Step-by-step explanation:
x=21+5y/8 as a fraction