What function is represented by this graph?
2 answers:
Answer:
See attachment
Step-by-step explanation:
You forgot to attach the graph.
However I will provide the graphs of all these functions.
Option A.
The function is . This is a logarithm function that has a horizontal asymptote at
and x-intercept at (1,0).
Option B
The function is . This is a polynomial function with x and y intercepts at the origin. The degree is odd and the leading coefficient is positive. As x grows negatively larger he graph goes down on the left. As x grows larger positively, the graph goes up on the right.
Option C.
The function is . This is an exponential function. The graph grows geometrically as x grows bigger positively. The negative x-axis is an asymptiote. The y-intercept is (0,1).
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<u>Answer-</u>
<em>The value of x is </em><em>10</em>
<u>Solution-</u>
When two lines are crossed by another line (transversal), the angles in matching corners are called Corresponding Angles.
When the line are parallel the corresponding angles are equal in measurement.
As m and n are parallel line, so
=[(sinx/cosx)/(1+1/cosx)] + [(1+1/cosx)/(sinx/cosx)]
=[(sinx/cosx)/(cosx+1/cosx)]+[(cosx+1/cosx)/(sinx/cosx)]
= [sinx/(cosx+1)] + [(cosx+1)/sinx]
= [sin^2x+(cosx+1)^2] / [sinx (cosx+1)]
= [2+2cosx] / [sinx(cosx+1)]
=[2(cosx+1)] / [sinx (cosx+1)]
= 2/sinx
= 2 cscx
(I think this will be helpful for you. if you can see the picture, it has more detail in it.)
=[(sinx/cosx)/(cosx+1/cosx)]+[(cosx+1/cosx)/(sinx/cosx)]
= [sinx/(cosx+1)] + [(cosx+1)/sinx]
= [sin^2x+(cosx+1)^2] / [sinx (cosx+1)]
= [2+2cosx] / [sinx(cosx+1)]
=[2(cosx+1)] / [sinx (cosx+1)]
= 2/sinx
= 2 cscx
(I think this will be helpful for you. if you can see the picture, it has more detail in it.)