Answer:
idk aljebra 2 either and i just got the same question how?
Step-by-step explanation:
Answer: a=4, b=-8, c=-3
Step-by-step explanation: This equation isn't in standard form. To get it there, subtract -3 from both sides. This gets you an equation of 4x^2-8x-3.
The standard form is ax^2+bx+c.
A is the number before x^2 (4). B is the number before x, and since it's subtracted it's negative (-8). C is the last number, and since it's subtracted it's negative (-3).
3.1,3.2,3.3,3.4,3.5,3.6,3.7,3.8
Answer:
x = infinite amount of solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define Equation</u>
8(2x + 5) = 16x + 40
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute 8: 16x + 40 = 16x + 40
- Subtract 40 on both sides: 16x = 16x
- Divide 16 on both sides: x = x
Here we see that <em>x</em> does indeed equal <em>x</em>.
∴ <em>x</em> has an infinite amount of solutions.
