Given z=f(x,y),x=x(u,v),y=y(u,v), with x(1,3)=2 and y(1,3)=2, calculate zu(1,3) in terms of some of the values given in the tabl
stich3 [128]
The value of zu(1,3) using the data elements represented on the table of values is q + p
<h3>How to solve the calculus expression?</h3>
The given parameters are:
z = f(x, y)
x = x(u, v)
y = y(u, v)
Where
x(1, 3) = 2 and y(1, 3) = 2
To calculate zu(1,3), we make use of:
The values x(1, 3) = 2 and y(1, 3) = 2 mean that:
(x,y) = (2,2).
So, we have:
From the table of values, we have:
So, the equation becomes
Evaluate the product
Hence, the value of zu(1,3) is q + p
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You can test this using the equation: a^2 + b^2 = c^2.
24^2 + b^2 = 60^2
576 + b^2 = 3,600
b^2 = 3,024
b = 54.999
Since b is not a whole number, the side lengths do not form a Pythagorean triple.
Brainliest answer please!!!
(x + 5)(y + 10)
x(y + 10) + 5(y + 10)
x(y) + x(10) + 5(y) + 5(10)
xy + 10x + 5y + 50
Answer:
what full work.Everyone wants to know so we can help you.
Step-by-step explanation:
The missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.
<h3>What is a complex number?</h3>
It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have the roots of a quadratic equation:
5 ± 3i
To find the quadratic equation:
(x - (5+3i))(x - (5-3i))
= x² -10x + 34
The missing value is 10x
The quadratic equation is:
= x² -10x + 34
Thus, the missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.
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