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3 years ago

5p−3p+9+p+3? pls im failingg

Mathematics

1 answer:

Triss [41]3 years ago

7 0

Answer:

3p + 12

Step-by-step explanation:

5p -3p + 9 + p + 3

Move around the parts of the equation

5p -3p + p + 9 + 3

Add positive 9 to positive 3

5p -3p + p + 12

Add positive p to negative 3p

5p -2p + 12

Combine positive 5p and negative 2p together

3p + 12

I Hope That This Helps! :)

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2 years ago

HELP MEEEEEEEEEEEEEEEEEEEE

uysha [10]

$A=0.25^2+2*0.25\sqrt{\frac{0.25^2}{4}+ 1.2^2}$ Alright, lets get started.

The side of square base is given 0.25 in. (say a)

The height of pyramid is given 1.2 in. (say h)

The formula for surface area A is given below:

A=a^2+2a √(a^2/4+ h^2 )

Putting the value of a and h .

$A=a^2+2a\sqrt{\frac{a^2}{4}+ h^2}$

Putting the value of a and h

$A=0.25^2+2*0.25\sqrt{\frac{0.25^2}{4}+ 1.2^2} \\A=0.0625+ 0.5\sqrt{\frac{0.0625}{4}+ 1.44} \\A=0.0625+ 0.5\sqrt{0.015625 + 1.44} \\A=0.0625+ 0.5\sqrt{1.455}\\A=0.0625+ 0.5*1.20\\A=0.0625+ 0.60\\A = 0.6625 square inches$

Hence the area of pyramid is 0.6625 square inches. : Hope it will help :)

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