Answer:You're selling tickets to a school play priced at $5 for students, $10 for parents, and $20 for general admission. The total sales are $2,500, you sell twice as many parent tickets as student tickets, and you selll 10 more students tickets than general admission. How many of each ticket did you sell?
Step-by-step explanation:
8x + 114x + 3
8x + 114x = 122x
112x + 3
The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
