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3 years ago

1.) (2)(8+2i)= Multiplying complex numbers

Mathematics

2 answers:

Anna35 [415]3 years ago

7 0

Answer:

Step-by-step explanation:

7+3i

Nutka1998 [239]3 years ago

4 0

Your answer is 16+4i

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Help again...its for math offering 15 points

Anettt [7]

Answer:

$\tan \dfrac{\theta}2 = \dfrac{1}2$

Step by step Explanation:

$\sin \theta = \dfrac{\text{Perpendicular} }{\text{Hypotenuse}} = \dfrac{12}{15}\\\\\\\cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}= \dfrac{9}{15}\\\\\text{Now,}\\\\\tan \dfrac{\theta}2 = \dfrac{\sin \tfrac{\theta}2}{\cos \tfrac{\theta}2}\\\\\\~~~~~~~~=\dfrac{2\cos \tfrac{\theta}2 \sin \tfrac{\theta}2 }{2\cos^2 \tfrac{\theta}2}~~~~~~;\left[\text{Multiply by}~ 2\cos\tfrac{\theta}2 \right]$

$=\dfrac{\sin \theta}{1+ \cos \theta}~~~~~~~~~~~~;[2 \sin x \cos x = \sin 2x ~ \text{and}~ 2\cos^2 x =1+\cos 2x]\\\\\\=\dfrac{\tfrac{12}{15}}{1+ \tfrac{9}{15}}\\\\\\=\dfrac{\tfrac{12}{15}}{\tfrac{24}{15}}\\\\\\=\dfrac{12}{15}\times \dfrac{15}{24}\\\\\\=\dfrac{12}{24}\\\\\\=\dfrac{1}2$

4 0

2 years ago

Mr. Z constructs a cube with 512 magnetic blocks. Students in his two classes will each make an identical cube. There are 28 stu

netineya [11]

25 plus 28 equals 53 and 512 times 53 is 27,136 so he will need 27,136 blocks for all of his students hope this helped

8 0

4 years ago

What is x + 100 = 263? A. 63 B.313 C.163 D.363

nevsk [136]

Answer:

Step-by-step explanation:

Subtract 100 from both sides to get x by itself.

x = 163

(Another way of writing this is "263 - 100 = " like you would see in elementary school.)

3 0

3 years ago

Read 2 more answers

Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5

lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer: v = 5v + 4u + 1.5sin(3t),

1.5sin(3t)

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1

v represents the "velocity function" i.e v = u'(t)

As v = u'(t)

u' = v

since u' = v

v' = u"

v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )

= 5v + 4u + 1.5sin(3t) ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ = $\left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]$ $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ + $\left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]$