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Blizzard [7]
3 years ago
12

There are four blood types, and not all are equally likely to be in blood banks. Records in a local blood bank show that, histor

ically, 49% of donations are type O blood, 27% are type A blood, 20% are type B blood, and 4% are type AB blood. The blood bank takes a random sample of 40 donations from the past month, and finds that 25 were type O, 10 were type A, 4 were type B, and 1 was type AB. The blood bank will run a chi-square test for goodness of fit to determine if the sample shows evidence that the distribution of blood types this month differs from the historical distribution. Are the conditions for such a test met
Mathematics
1 answer:
zvonat [6]3 years ago
3 0

Answer:

No, because all the expected frequencies must be higher than 5.

Step-by-step explanation:  

The chi-square test might be performed in those situations in which we need to know if a series of observations adjust or not to a theoretical function, such as the normal, Poisson, or binomial.

The chi-square test does not require the number of files to coincide with the number of columns in the table. It does not establish any restriction about the number of modalities per variable. However, the expected frequencies or counts should not be less than five.

In the exposed example, this unique rule is not accomplished, so the chi-square test can not be performed.  

 

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Which of the following values does not satisfy the inequality-2x-6is less than or equal to 1 A)-4 B)-3 C)-2 D)-1
GaryK [48]
-2x - 6 < = 1
-2x < = 1 + 6
-2x < = 7...change the inequality sign when dividing by a negative number
x > = -7/2
x > = - 3.5

the one that does not satisfy the inequality is : -4...because it is less then -3.5
3 0
3 years ago
1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav
OLga [1]

Answer:

(1) y=C, C\neq0

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant,  C \neq 0, has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

\Rightarrow x=C, where C\neq0.

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0
3 years ago
As the amount of time on homework increased, their grade in class ____________.
omeli [17]

Answer:

Increases

Step by Step Explanation:

More time on your homework means more time to cheat/figure the answer out.

8 0
3 years ago
Read 2 more answers
One out of 3 gym members say they spent 5 hours per week at the gym. If there are 150 people working out at the gym, how many wi
lana [24]

Answer: 50

Step-by-step explanation:

From the question, we are informed that 1/3 of gym members say they spent 5 hours per week at the gym.

Assuming there are 150 people working out at the gym, the number of people that'll most likely spend 5 hours at the gym this week will be calculated by multiplying 1/3 by 150. This will be:

= 1/3 × 150

= 50 people

8 0
3 years ago
A calculus exam has a mean of µ = 73 and a standard deviation of σ = 4. Trina's score on the exam was 79, giving her a z-score o
kirza4 [7]

Answer:

I get z = +1.8

x= 79

m= 73;s= 4;z= (x-m)/s= 1.5

hope it helps you

7 0
3 years ago
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