Answer:
210 miles
Step-by-step explanation:
70x3 70mph for 3 hours
Answer:
Percent increase
Step-by-step explanation:
Since the number of marching band students increased from 304 to 322, you would find the percent increase.
You wouldn't find the percent decrease because the number of students increased.
So let f(x) = x^(2/3)
<span>Then let f'(x) = 2/3 x^(-1/3) = 2 / (3x^(1/3)) </span>
<span>When x = 8, </span>
<span>f(8) = 8^(2/3) = 4 </span>
<span>f'(8) = 2 / (3*8^(1/3)) = 1/3 </span>
<span>So near x = 8, the linear approximation is </span>
<span>f(x) ≈ f(8) + f'(8) (x - 8) </span>
<span>f(x) ≈ 4 + 1/3 (x - 8) </span>
<span>So the linear approximation for x = 8.03 is... </span>
<span>f(8.03) ≈ 4 + 1/3 (8.03 - 8) </span>
<span>f(8.03) ≈ 4 + 1/3 (0.03) </span>
<span>f(8.03) ≈ 4.01 </span>
<span>8.03^(2/3) ≈ 4.01 </span>
Answer:
9. (7a + 6b – 9c) – (3a – 6c)
=7a+6b-9c-3a+6c
=7a-3a+6b-9c+6c
=4a+6b-3c
10. (x2 – 9) – (-2x2 + 5x – 3)
= x^2-9+2x^2-5x+3
=x^2+2x^2-5x-9+3
=3x^2-5x-6
11. (5 – 6d – d2) – (-4d – d2)
=5-6d- d^2+4d+ d^2
=5-6d+4d-d^2+ d^2
=5-2d
12. (-4x + 7) – (3x – 7)
=-4x+7-3x+7
= -4x-3x+7+7
=-7x+14
13. (4a – 3b) – (5a – 2b)
=4a-3b-5a+2b
=4a-5a-3b+2b
= -a-b
14. (2c + 3d) – (-6d – 5c)
=2c+3d+6d+5c
=2c+5c+3d+6d
=7c+9d
15. (5x2 + 6x – 9) – (x2 – 3x +7)
=5x^2+6x-9- x^2+3x-7
=5x^2- x^2+6x+3x-9-7
=4x^2+9x-16
16. (3y – 6) – (8 – 9y)
=3y-6-8+9y
=3y+9y-6-8
=12y-14
17. (3a2 – 2ab + 3b2) - (-a2 – 5ab + 3b2)
=3a^2-2ab+3b^2+ a^2+5ab-3b^2
=3a^2+ a^2-2ab+5ab+3b^2- 3b^2
=4a^2+3ab
18. 5c – [8c – (6 – 3c)]
=5c-[8c-6+3c]
=5c-8c+6-3c
=5c-8c-3c+6
= -6c+6
19. 10x + [3x – (5x – 4)]
=10x+[ 3x-5x+4]
=10x+3x-5x+4
=8x+4
20. 3x 2 – [7x- (4x – x2) + 3]
=3x^2-[7x-4x+ x^2+3]
=3x^2-7x+4x- x^2-3
=3x^2-x^2-7x+4x-3
=2x^2-3x-3
21. x2 – [ - 3x+ ( 4 – 7x)]
= x^2-[ -3x+4-7x]
= x^2+3x-4+7x
= x^2+3x+7x-4
= x^2+10x-4
Answer:
C(t) = I/F [1 - e^(-Ft/V) ] + C₀e^(-Ft/V)
as t = 0 ; C(t) = 1/F
Explanation:
dC/dt) = (-F/V)*C+(I/V)
To make it easier to solve, let
Constants: I, V,F
Variables: C, t
workings and solution can be viewed below
