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Tpy6a [65]
3 years ago
9

Which is larger, 9 kilograms or 8,500 grams?

Mathematics
2 answers:
AfilCa [17]3 years ago
5 0

Answer: 9 kilograms

Step-by-step explanation:

mestny [16]3 years ago
5 0

9 kilograms is larger because the kilogram, or kilogramme, is the base unit of weight in the Metric system. It is the approximate weight of a cube of water 10 centimeters on a side. While a gram is a unit of weight equal to 1/1000th of a kilogram. A gram is the approximate weight of a cubic centimeter of water.

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A soccer ball is kicked into the air from the ground. If the ball reaches a maximum height of 25 ft and spends a total of 2.5 s
OLga [1]
Hello,

g=9.81m/s²= 9.81/0.3048 =32.18.. ft/s² rounded to 32

h=-g/2*t²+vt+h0
if t=0,h=0 ==>h0=0

==>h=-16*t²+vt
50 ft in 2.5s ==> 25 ft in 1.25s

25=-16*1.25²+v*1.25
==>v=50/1.25=40

Equation h=-16t²+40*t


4 0
3 years ago
Read 2 more answers
Write down the nth term of this sequence 2,7,12,17,22
ki77a [65]
There is a pattern. Each number is added by 5. So take 22 and add 5 to get 27. Just repeat until you find your answer, which would be 42.
6 0
3 years ago
Read 2 more answers
The length of the flower garden is 3 times as great as the wish what are the dimensions of the flower garden if the area is 48
Natalka [10]

Answer:

4 units by 12 units

Step-by-step explanation:

one side of the rectangle is x, the other side is 3x.

3x(x)=48

3x²=48

x²=48/3

x²=16

√x²=√16

x=4

substitute 4 into the original dimensions

5 0
4 years ago
1.) The independent variable x is missing in the given differential equation. Proceed as in Example 2 and solve the equation by
mixas84 [53]

Answer:

The solution to the differential equation y'(y + 7)y'' = (y')²

y = Ae^(Kx) - 7

Step-by-step explanation:

Given the differential equation

y'(y + 7)y'' = (y')² ..................(1)

We want to solve using the substitution u = y'.

Let u = y'

The u' = y''

Using these, (1) becomes

u(y + 7)u' = u²

u' = u²/u(y + 7)

u' = u/(y + 7)

But u' = du/dy

So

du/dy = u/(y + 7)

Separating the variables, we have

du/u = dy/(y + 7)

Integrating both sides, we have

ln|u| = ln|y + 7| + ln|C|

u = e^(ln|y + 7| + ln|C|)

= K(y + 7)

But u = y' = dy/dx

dy/dx = K(y + 7)

Separating the variables, we have

dy/(y + 7) = Kdx

Integrating both sides

ln|y + 7| = Kx + C1

y + 7 = e^(Kx + C1) = Ae^(Kx)

y = Ae^(Kx) - 7

8 0
4 years ago
Homework J
shtirl [24]

Answer:

ga = 14

gb = 17

Explanation:

It's just simply replacing the empty spaces (let's call those x) and doing the necessary operations. If I gave you T = 10 + x, T would be equal to 10x. Similarly, in the first problem we replace x with the given number g and then do all our operations (T = 10 + g(4)), in the second one, we also have to remember that the formula to calculate T is T = 10 + g. Knowing that, we replace the first blank (y) with 10, and the second blank with our given number g. I hope you do well :D

5 0
4 years ago
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