Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Answer:
8
Step-by-step explanation:
J'espère que cela t'aides! si c'est le cas, puis-je avoir un brainliest ?
H is the number of hours worked. So the expression 200h+250 is 200 times the number of hours plus 250.
Here's a few computations using different values for h
1 hour --> (200)(1)+250 = 450
2 hours --> (200)(2) + 250 = 650
3 hours --> (200)(3)+250 = 850
10 hours --> (200)(10)+250 = 2250
As you can see the 250 is fixed. It gets added to the cost no matter how many hours the lawyer works. This is most likely a flat fee. Just to meet the lawyer you pay $250.
The 200 gets multiplied by the hours worked. So the 200 is an hourly rate. The more hours the lawyer works, the more he gets paid because this part of the expression depends on the hours worked.
Thus, an interpretation of the expression 200h + 250 is that the lawyer charges a fee of $250 per consultation and an additional $200 per hour on top of that.
Given:
The expression is:
To find:
The difference.
Solution:
We have,
It can be rewritten as:
Taking LCM, we get
Therefore, the value of the difference is 
.
