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2 years ago

Can someone pls help

Mathematics

1 answer:

Len [333]2 years ago

6 0

Answer:

I believe the answer is D

Step-by-step explanation:

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If it is all calculated together correctly then the final answer would be 25%.

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2 years ago

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A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He gained weight at a rate of 5.55.55

Juli2301 [7.4K]

Answer:

The equation for the relationship between the weight and number of months is $W(t)= 5.5t+79.5$

Step-by-step explanation:

we know that

A linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept (value of y when the value of x is equal to zero)

or say b is the actual weight of the wrestler.

In this problem

m=5.5 kg/month

Let

W ⇒ the sumo wrestler's weight in kg (dependent variable)

t ⇒ the time in months (independent variable)

The linear equation is equal to

$W(t)=5.5t+b$

where

b is the actual weight when he started the diet.

Now Given

W = 140 kg

t = 11 months

substitute in the linear equation to find the value of b

$140 = 5.5\times11 +b\\140 = 60.5+b\\b = 140-60.5\\b = 79.5\ kg$

$W(t)= 5.5t+79.5$

Hence,The equation for the relationship between the weight and number of months is $W(t)= 5.5t+79.5$

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2 years ago

\left(3x-5\right)+\left(x+6\right)

ryzh [129]

I'm sorry but I couldn't really get that can u at least take a picture or something

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2 years ago

It costs $3.56 to buy a pack of pencils. Which of the following equations shows the amount of money needed, x, to buy k packs of

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Hope I helped! ^-^

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3 years ago

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1.08t can be written as (1.081/12)12t to give the approximate equivalent monthly interest rate based on an annual rate of 8%. Us

kobusy [5.1K]

Because t is given in years and 1.08 = 1 + 0.08, the annual percent increase
is 8%.
To find the monthly percent increase that gives an 8% annual increase,
use the fact that
t = $\frac{1}{12} * 12 t$ 
and the properties of exponents to rewrite the
model in a form that reveals the monthly growth rate.

$1.08^{t} 
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= 1.0064634^{12t}$

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2 years ago

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