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FinnZ [79.3K]
3 years ago
7

Beverly drew the line AB shown below. She then constructed line DC which is the perpendicular bisector of AB.

Mathematics
1 answer:
earnstyle [38]3 years ago
5 0

Answer:

D

Line segments are congruent due to the side-angle-side congruence postulate.

Step-by-step explanation:

DC is the perpendicular bisector of line AB, this mean that DC divides AB at 90 degrees into two equal parts at point E. Hence:

AE = BE

Also DE ≅ DE (reflexive property of congruence)

Also ∠AED = ∠BED = 90° (perpendicular bisector)

We can therefore say that triangle AED and triangle BED are congruent according to the side-angle-side congruence theorem. Therefore line AD = line BD

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Factor completely: 80x2 – 125
Paladinen [302]

Answer:

5(4x-5)(4x+5)

Step-by-step explanation:

80x^2-125= \\\\5(16x^2-25)= \\\\5(4x-5)(4x+5)

Hope this helps!

6 0
3 years ago
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What is the slope of the line for BOTH graphs? Are the slopes the same or different?
Y_Kistochka [10]

Answer:

both are -10

Step-by-step explanation:

#1

x1 y1  x2 y2

1.5 180  6 135

(Y2-Y1) (135)-(180)=   -45  ΔY -45

(X2-X1) (6)-(1.5)=    4.5  ΔX 4.5

slope= -10          

B= 195          

Y =-10X +195

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~    

#2

x1 y1  x2 y2

1 175  8 105

   

(Y2-Y1) (105)-(175)=   -70  ΔY -70

(X2-X1) (8)-(1)=    7  ΔX 7

slope= -10          

B= 185          

Y =-10X +185    

7 0
3 years ago
How to find the missing angle of a parallelogram only knowing 1 number?
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Answer:  
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4 0
4 years ago
OC and OR are similar. Find the length of QP.
Elena L [17]

Given:

Circle C and circle R are similar.

The length of arc AB is s = \frac{22 \pi}{9}

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s,  r and \theta is

arclength = 2\pi r \frac{\theta}{360}

where,

s be the length of the arc

r be the radius

\theta be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}

or, 2r \frac{\theta}{360} = \frac{22}{9} [ eliminating \theta from both side]

or, \theta = \frac{(22)(360)}{(9)(2)(4)}

or, \theta = 110^\circ

Again,

For circle R

Taking, r = 6 and \theta = 110^\circ we get,

The length of arc QP is

arc length = 2\pi (6)(\frac{110}{360} )

or, arclength = \frac{11 \pi}{3}

Hence,

The length of QP is \frac{11 \pi}{3}. Option C.

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