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Tresset [83]
3 years ago
8

A 10 meter ladder is leaned up against a building. If

Mathematics
1 answer:
kirill115 [55]3 years ago
5 0

Answer:

8.7

Step-by-step explanation:

Use trigonometry. The ladder and the building form a right triangle with the ground. You are given the length of the hypotenuse and the base angle. You use sine since we are trying to figure out the opposite side from the angle and we have the hypotenuse length. Sin = opposite/hypotenuse. So in this case, sin 60°= x/10. We solve for x by multiplying both sides by 10. Now x= sin 60° (10) = (0.8660)(10) = 8.7 m.

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The mode is 1 and the range is 3.22
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A yoga studio offered a special for high school students where new students could join for half off of the monthly fee (includes
Eva8 [605]

Given:

  • the discounted price was offered by the yoga studio at 50% off the regular price 'r' (monthly fee).
  • the one-time processing fee is $8.25
  • 10 students took this offer and the yoga studio collected $392.50

To Find:

The regular price of the monthly fee 'r'

Solution:

The equation can be framed as

(r-\frac{50}{100}.r)+8.25=39.25\\\frac{50}{100}.r+8.25=39.25\\\frac{r}{2}+8.25=39.25\\\frac{r}{2}=31\\r=(31)(2)=62

And, the regular price of the monthly fee is $62.

Calculation:

We know that 10 students took the offer and the yoga studio collected $392.50. This means, using the Unitary Method, the studio has collected $(392.50/10) = $39.25 per student.

Now, if r denotes the regular price of the monthly fee, the offer runs a 50% discount on r.

So, the discounted price should be $(r - 50% of r) i.e., r-\frac{50}{100}.r

We must add to this the one time processing fee of $8.25

Therefore, the total price paid by one student would be

(r-\frac{50}{100}.r)+8.25

This must be equal to $39.25 as we have calculated this to be the amount collected by the yoga studio per person.

So, the equation can be framed as

(r-\frac{50}{100}.r)+8.25=39.25\\\frac{50}{100}.r+8.25=39.25\\\frac{r}{2}+8.25=39.25\\\frac{r}{2}=31\\r=(31)(2)=62

Thus, the regular price of the monthly fee is $62.


5 0
3 years ago
A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a
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K · ( 0, 0 ) = ( 0 , 0 )
k · ( 0 , 4 ) = ( 0 , 10 )
k · ( 6, 0 ) = ( 15, 0 )
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8 0
4 years ago
Quadrilateral HJKL ~ Quadrilateral MPNQ<br><br> Which statements must be true
LenKa [72]

Answer:

m∠K =m∠N

HJ/MP=JK/PN

Step-by-step explanation:

The picture of the question in the attached figure

we know that

if two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

<u><em>Verify each statement</em></u>

case a) we have

m∠K =m∠N

The statement is true

Because, angle K and angle N are corresponding angles, and remember that in similar figures corresponding angles are congruent

case b) we have

HJ≅MP

The statement is false

Segment HJ and segment MP are proportional, not congruent

case c) we have

m∠J≅m∠N

The statement is false

Because angle J and angle N are not corresponding angles

case d) we have

HJ/MP=JK/PN

The statement is true

Because, the ratio of its corresponding sides is proportional

so

\frac{HJ}{MP}=\frac{JK}{PN}=\frac{KL}{NQ}=\frac{HL}{MQ}

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3 years ago
_____ is another way of making numbers easier to work with when we don’t need to know exactly how many
zubka84 [21]

If you give me the options I can give the answer to you.

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3 years ago
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