Answer: $9.00
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Answer:
0.281 ; 0.864
Step-by-step explanation:
1.)
p decreases as n increases (n increases, p--> 0)
λ ≥ 0
P(x = x) = (e^-λ * λ^x) ÷ x!
λ for Ford = 1.27
B) zero problems :
P(x = 0) :
(e^-1.27 * 1.27^0) ÷ 0! = 0.281
P(x = 0) = 0.281
Two or fewer problems :
P(x ≤ 2) = p(x = 0) + p(x = 1) + p(x = 2)
P(x ≤ 2) = 0.281 + 0.357 + 0.226
P(x ≤ 2) = 0.864
D.) It allows for early detection and thus adequate curtailment of the problem at an a stage in which it seems easier to curb.
i belive it is xy^2 but tell me if ou need more
Answer:
There are a few ways:
You can do counting like this...
1000
999
998
997
996
995
994
993
Another better and faster way will be to do 3+990
The reason is becuase 7-10=3 and also that we can remove the 10 from 1000
So those were 2 ways how she can subtract CORRECTLY!
Have a great day!
:D
