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arlik [135]
3 years ago
10

Which expression is equivalent to cos(3x) sin x?

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
7 0

Answer:

Step-by-step explanation: I tried all the other options and this was the only correct one for me on Edmentum.

LuckyWell [14K]3 years ago
4 0

Answer:

\frac{1}{2} [sin(4x)-sin(2x)]

Step-by-step explanation:

Use the Product-Sum identity to turn cos(3x) sin x into a sum.

Formula: cos(u) + sin(v) = \frac{1}{2}[sin(u+v)-sin(u-v)]

Plug 4x and 2x for u and v into the formula: \frac{1}{2}[sin(3x+x)-sin(3x-x)]

Simplify: \frac{1}{2}[sin(4x)-sin(2x)]

:)

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Answer:

106.8

Step-by-step explanation:

17 * 2 = 34

34 * pi = 106.8

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4 years ago
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5 0
3 years ago
There's so many numbers in this one shape I'm confused ._.
Svetlanka [38]
The answer should be 12 units^2

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7 0
3 years ago
Read 2 more answers
Determine which consecutive integers do not have a real zero of between them. a. (–6, –5) c. (–2, –1) b. (–5, –4) d. (1, 2) Plea
svetoff [14.1K]
We have by the intermediate value theorem that if a continuous function takes values both above and below zero at 2 points, there is a zero of the function in-between. We have that polynomials are continues. Let's calculate f(-6) and f(-5). f(-6)=-36 while f(-5)=-1. Thus, we cannot conclude that there is a root between them.
F(-2)=8, f(-1)=-1, so there is a flip; a zero must exist between them.
F(1)=-1, f(2)=20, so again there is a change of signs.
f(-5)=-1, f(-4)=14 so there is a root still.
We have that the only choice that does not have a root between the integers is choice a.

7 0
3 years ago
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Angelina_Jolie [31]

Answer:

The answer is C

Step-by-step explanation:

Please mark me Brainliest

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