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lilavasa [31]
3 years ago
14

Can someone plz help this is my third time posting this question and I’m trying to get an 92

Mathematics
2 answers:
Harrizon [31]3 years ago
6 0

Answer:

the last three answers is what i think

Step-by-step explanation:

Black_prince [1.1K]3 years ago
3 0

21 is the right answer.

180-138=42°

and since it is given in the question that the triangle is isoceles ,so half of 42 is 21°

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PLEASE HELP! NEED IT NOW!
insens350 [35]

Answer:

ok

Step-by-step explanation: 3cm i believe

3 0
2 years ago
The sum of half a number and two-thirds of the number is less than 14
Gre4nikov [31]
Suppose the number is y >>>>>So y/2 +2y/3 <14 
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3y + 4y < 84
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y           <84/7
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5 0
3 years ago
When debby's 3ds is fully charged it last for 8 hours. if she only charged it 3/5 full how long did it last her?
Luba_88 [7]
8*3/5=4.8 hours

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7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP PLEASE
emmainna [20.7K]

Answer:

The equation that represents the line passing through the point (2, -4) with a slope of one half is

f(x) = \frac{1}{2}x - 5

Step-by-step explanation:

The equation of a line can be described by a first order equation in the following format:

f(x) = ax + b

In which a is the slope of the line.

Solution:

The line slope is \frac{1}{2}, so a = \frac{1}{2}.

The equation of the line now is:

f(x) = \frac{1}{2}x + b

The problem states that the line passes through the point(2,-4). This means that when x = 2, f(x) = -4

So:

f(x) = \frac{1}{2}x + b

-4 = \frac{1}{2}*(2) + b

-4 = 1 + b

b = -5

So, the equation that represents the line passing through the point (2, -4) with a slope of one half is

f(x) = \frac{1}{2}x - 5

3 0
3 years ago
(1 point) Consider the function f(x)=−x3+2x2+2x+1 Find the average slope of this function on the interval (−2,6). equation edito
Whitepunk [10]

Answer:

Step-by-step explanation:

Given is a function

f(x)=-x^3+2x^2+2x+1

f(6) = -6^3+2(6^2)+2(6)+1\\=-131\\

f(-2) = -(-2)^3+2(-2)^2+2(-2)+1\\=13

Average slope of this function is change of f(x) in (-2,6)/change of x in (-2,6)

= \frac{-131-13}{8} \\=-18

By mean value theorem there exists a c such that f'(c) = -18

i.e. -3x^2+4x+2 =-8\\3x^2-4x-10 =0\\

Using quadratic formula

x = 2.61, -1.277

Out of these only 2.61 lies in the given interval

c = 2.61

7 0
4 years ago
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