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borishaifa [10]
3 years ago
13

Which is equivalent to (4xy – 3z)2, and what type of special product is it?

Mathematics
2 answers:
bazaltina [42]3 years ago
6 0
Hello,

Answer D
16x²y²-24xyz+9z² a perfect square trinomial  which
le square of the difference of 3z from 4xy.
k0ka [10]3 years ago
3 0

Answer:

16x^2y^2-24xyz +9z^2

Step-by-step explanation:

(4xy - 3z)^2

Given expression has exponent 2, so we multiply it twice

(4xy - 3z)(4xy-3z)

Apply FOIL method to multiply the parenthesis

multiply 4xy inside the second parenthesis

and multiply -3z inside the second parenthesis

4xy(4xy-3z)=16x^2y^2-12xyz

-3z(4xy-3z)=-12xyz+9z^2

16x^2y^2-12xyz-12xyz+9z^2

Combine like terms

16x^2y^2-24xyz +9z^2

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Question #45 plz all answers will help
Veseljchak [2.6K]
To solve this, you can use this equation:

1530 ÷ 15 = x

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3 years ago
The sum of two numbers is 54. The smaller number is 18 less than the larger number. What are the numbers?
igomit [66]

Answer:

The larger number is 37.  This makes the smaller number 56 - 37, which is 19.

Step-by-step explanation:

 

The first step is to pick variables for the two numbers.  Lets call the smaller number x and the larger number y.

Since the sum of the two numbers is 56, this means that x + y = 56.  Let's call this equation 1 and save it for later.

 

The next sentence says:

The smaller number is 18 less than the larger number.  So, 18 less than the larger number would be y - 18.  So, the smaller number must be equal to this, so

 

x = y - 18

 

Replace the x in equation 1 with y - 18

 

x + y = 56

(y-18) + y = 56   (replace x with y-18)

2y - 18 = 56        (add the y's)

2y = 74               (add 18 to both sides)

y = 37                 (divide both sides by 2)

 

So, the larger number is 37.  This makes the smaller number 56 - 37, which is 19.

 

Hope this helps!!  :)

8 0
2 years ago
Multiply the polynomials show steps
Karo-lina-s [1.5K]

Answer:

3a^{4} + 11a³ - 7a² + 18a - 18

Step-by-step explanation:

<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>

(a² + 4a - 6) × (3a² - a + 3) =

(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}

<u>Now we can evaluate the terms in the brackets. </u>

(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3} =

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)

<u>We can open the brackets now. One plus and one minus makes a minus. </u>

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18

<u>Evaluate like terms.</u>

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3a^{4} + 11a³ - 7a² + 18a - 18

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Answer: x 50 y 5

Step-by-step explanation: In the graph

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2 years ago
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