Geometry student reference sheet

Which fractions are equivalent to 15/20

Digiron [165]

Answer:

$\frac{3}{4}$ , $\frac{30}{40}$ , $\frac{45}{60}$ , $\frac{60}{80}$ ....e.t.c are all equivalent fractions

Step-by-step explanation:

For the answer you need to know bout equivalent fractions

TO find equivalent fractions you have to multiply the numerator and denominator by the same amount

E.x. $\frac{15}{20}=\frac{(15)(2)}{(20)(2)} =\frac{30}{40}$

Therefore $\frac{30}{40}$ is an equivalent fraction

8 0

2 years ago

An aluminum can is a right cylinder. Find the amount of paper needed for the can's label and the total amount of aluminum needed

statuscvo [17]

Answer:

you did not specify the diamiter of the can please add another question and i will help

Step-by-step explanation:

it is imposible to answer right now

6 0

2 years ago

Estimate the equation 12+ 19.61

Mandarinka [93]

QUESTION:

QUESTION:estimate the equation 12+19.61.

QUESTION:estimate the equation 12+19.61.Answer:

QUESTION:estimate the equation 12+19.61.Answer:12+19.61 =31.61.

4 0

3 years ago

Read 2 more answers

A research study investigated differences between male and female students. Based on the study results, we can assume the popula

garri49 [273]

Using the normal distribution and the central limit theorem, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of $\mu = 3.5$ .

The standard deviation is of $\sigma = 0.5$ .

Sample of 100, hence $n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05$

The interval that contains 95.44% of the sample means for male students is between Z = -2 and Z = 2, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$