For y=x^2-6x-11
complete the square
so roots
set y=0
0=x^2-6x-11
group x terms
0=(x^2-6x)-11
take 1/2 of linear coefient (-6) and square it
-6/2=-3, (-3)^2=9
add positive and neative to inside of parenthasees
0=(x^2-6x+9-9)-11
complete square
0=((x-3)^2-9)-11
expand
0=(x-3)^2-9-11
0=(x-3)^2-20
add 20 to both sides
20=(x-3)^2
sqrt both sides
remember positive and negative roots
+/-2√5=x-3
add 3 to both sides
3+/-2√5=x
so
x=3+2√5 and 3-2√5
The sum is 1625.
Answer in Words: One thousand and six hundred twenty-five.
The cube of 10 is 1000.
10 X 10 = 100 (square of ten)
100 x 10 = 1000 (cube of ten)
The square of 25 is 625.
25 x 25 = 625 (square of 25)
Therefore, 1000 + 625 = 1625
the sum is 1625
Answer:
The sum of the interior angles with n number of sides is solved through the equation,
S = 180 x (n - 2)
For 37 - gon,
S = 180 x (37 - 2) = 6300
Thus, the sum of the interior angles of a 37-gon is 6300°
Step-by-step explanation:
Use vertical pipes around the value.
Example:
abs(-4) = |-4| = 4
