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3 years ago

Plot the image of point A under a reflection across line l.

Mathematics

2 answers:

Bingel [31]3 years ago

8 0

To plot the reflected point of A under a reflection across line l, just move 8 units across the line "l" horizontally.

The reflected point of A should be written as A'.

sergiy2304 [10]3 years ago

4 0

Answer:

Just from point a go 8 spaces to the left and place the dot over there.

Step-by-step explanation:

Since you are getting a reflection of a you need to move 4 spaces to the left of the line to get an exact mirror of point a or relfelction.

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3. A prop for the theater club's play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round

Maksim231197 [3]

Answer:

8138.88 cubic unit.

Step-by-step explanation:

Given that,

Radius, r = 12

Height, h = 18

We need to find the volume of the prop. The volume of a cylinder is given by the formula as follows :

$V=\pi r^2 h\\\\V=3.14\times 12^2 \times 18\\\\V=8138.88\$

So, the volume of the cylinder is 8138.88 cubic unit.

6 0

3 years ago

8 less than the quotient of 18and a number m

antoniya [11.8K]

Answer:

8-18/m

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3 years ago

How much of each ingredients did the store use (50 Points)

avanturin [10]

If you simply want to multiply the answers given to you I would say answer c. 6lbs peanuts, 3 pound almonds and 2lb raisins. If you multiply 6*1.50 you get 9, you multiply 3*3.00 would also equal 9, and 2*1.50 is 3. 9+9+3=21

4 0

3 years ago

A 41 gram sample of a substance that's used to detect explosives has a k-value of 0.1392. Find the substance's half life, in day

-BARSIC- [3]

Answer:

The substance half-life is of 4.98 days.

Step-by-step explanation:

Equation for an amount of a decaying substance:

The equation for the amount of a substance that decay exponentially has the following format:

$A(t) = A(0)e^{-kt}$

In which k is the decay rate, as a decimal.

k-value of 0.1392.

This means that:

$A(t) = A(0)e^{-0.1392t}$

Find the substance's half life, in days.

This is t for which $A(t) = 0.5A(0)$ . So

$A(t) = A(0)e^{-0.1392t}$

$0.5A(0) = A(0)e^{-0.1392t}$

$e^{-0.1392t} = 0.5$

$\ln{e^{-0.1392t}} = \ln{0.5}$

$-0.1392t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.1392}$

$t = 4.98$

The substance half-life is of 4.98 days.

5 0

3 years ago

F(x)=8^x+7 what is f(3)

goldenfox [79]

Answer:

Step-by-step explanation:

f(3) = 8^3 + 7 = 512 + 7 = 519

4 0

3 years ago