Answer:
Step-by-step explanation:
Given that transitor has a 2% defective rate, need to calculate the probability that the 10th transistor produced is the first with a defect.
The probability function is p(x=k) = (1-p)^(n-1) * p
p = (1-defective rate)^(n-1) * defective rate; n=10
p = (1-0.02)^9 * 0.02 = 0.98^9 * 0.02 = 0.01666
In the 500 spin test, 4 was chosen 121 times. This mean it was chosen 121 times out of 500, or 121/500.
Now, we need to convert this into a percent. We do this by dividing the numerator by the denominator, and multiplying the result by 100.
121/500 * 100 = 24.2, so the probability of spinning a 4 is 24.2%.
Answer:
question 2 is B. 3 units down
question 3 is B. 4 units down
Step-by-step explanation:
graphed it again luv <3
We can use the two point form to find the answer:

Where y1 is the y coordinate(coordinate on the right hand side of (-9)) of the of the first coordinates, and y2 is the y coordinates of the second coordinates given (0).
While x1(-9) and x2(-6) are the x-coordinates(left hand side of the coordinates) of the coordinates given seperately.
m is the slope of the two points, and the formula is:

In this case:

We can then proceed to find the eqaution by putting *one* of the points into the two-point formula.
Put (-6,0) into the formula:
-0-y = 3(-6-x)
-y = -18 - 3x
y = -(-18 - 3x)
y = 18 + 3x
Therefore the answer is y= 18+3x.
Hope it helps!