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3 years ago

Evaluate if x=2 and y=5 -3x+4y

Mathematics

1 answer:

babunello [35]3 years ago

6 0

Answer:

Step-by-step explanation:

-3(2)+4(5) multiply -3 and 2 then multiply 4 and 5

-6+20= add -6 to 20

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U Move It charges $16 per hour plus a fueling fee of $25 to rent a truck. Jamarcus needs to rent a truck and can spend no more t

bixtya [17]

Answer:

A. 16h+25≤125

Step-by-step explanation:

From the information, the one-time fee is $25.

The rate per hour is $16

Therefore the total cost involved in renting a car is given by:

16h+25

Jamarcus needs to rent a truck and can spend no more than $125.

This implies that:

16h+25≤125

The correct answer is A.

3 0

3 years ago

What is the height, width, and length

Novosadov [1.4K]

so, let's say the length is "L".

width = 2 shorter than L = L - 2.

height = 9 more than twice L = 2L + 9.

check the picture below.

keeping in mind that the volume of a <u>rectangular prism</u> is simply the product of its length, width and height, and since we know the volume has to be 45.

$\bf 45=(L)(L-2)(2L+9)\implies 45=(L)(2L^2+5L-18) \\\\\\ 45=2L^3+5L^2-18L\implies 0=2L^3+5L^2-18L-45 \\\\\\ \stackrel{\textit{now let's do some grouping}}{0=(2L^3+5L^2)-(18L+45)}\implies \stackrel{\textit{common factor}}{0=L^2(2L+5)-9(2L+5)}$

$\bf \stackrel{\textit{again common factor}}{0=\underline{(2L+5)}(L^2-9)}\implies \stackrel{\textit{difference of squares}}{0=(2L+5)\stackrel{\downarrow }{(L^2-3^2)}} \\\\\\ 0=(2L+5)(L-3)(L+3)\implies L= \begin{cases} -\cfrac{5}{2}\\[1em] \boxed{3}\\ -3 \end{cases}$

from those 3 factors, we get those solutions/zeros.

we can't use -5/2, or -3, because the length can't be a negative value, so L = 3.

that means the width = 3 + 2, and the height = 2(3) +9.

8 0

3 years ago

Mhanifa please help! Find the missing side. Round to the nearest tenth

forsale [732]

Answer:

12) x = 49.5

13) x = 8.5

14) x = 44.8

15) x = 4.6

Step-by-step explanation:

We can solve for the missing side lengths using trigonometry

Remember these are the trigonometric ratios

Sin = Opposite over Hypotenuse

Cos = Adjacent over Hypotenuse

Tan = Opposite over Adjacent

For #12

We can use trig ratio tangent as we are given an angle with a measure of 68° and its adjacent side length and we need to find the opposite side length. When dealing with opposite and adjacent we can use tan.

That being said we want to create an equation to solve for x

$tan(68)=\frac{x}{20}$

Now we solve

* multiply each side by 20 *

$20tan(68) = 49.5\\\frac{x}{20} 20=x\\$

we're left with x = 49.5

It seems that all of the problems are dealing with an angle, its opposite side and its adjacent side. So we will use the same trig ratio "tan" and process to solve for x.

For 13)

$tan(62)=\frac{16}{x} \\$