Answer:
it is non of the above. g is not a negitive in any but may be a cause 0 is a negitive and a posivtive
Step-by-step explanation:
Answer:
y=40
x=59
z=81
Step-by-step explanation:
therfore..40+59+81=180
Answer:
7: 11
Step-by-step explanation:
Sheep : pigs : total
4 7 4+7
4 7 11
Ratio of pigs to total
7: 11
Answer:
Step-by-step explanation:
Decay is defined by the function as,
f(t) = ![(1-\frac{r}{n} )^{nt}](https://tex.z-dn.net/?f=%281-%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bnt%7D)
Here, r = rate of decay
t = duration of decay Or time (In years)
n = Number of times of decay in a year
Decay every 2 years over a period of t years,
f(t) = ![(1-\frac{r}{\frac{1}{2}})^{\frac{1}{2}\times t}](https://tex.z-dn.net/?f=%281-%5Cfrac%7Br%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20t%7D)
= ![(1-2r)^\frac{t}{2}](https://tex.z-dn.net/?f=%281-2r%29%5E%5Cfrac%7Bt%7D%7B2%7D)
Therefore,
will be the answer.
Decay 2 times a year over a period of t years,
f(t) = ![(1-\frac{r}{2})^{2t}](https://tex.z-dn.net/?f=%281-%5Cfrac%7Br%7D%7B2%7D%29%5E%7B2t%7D)
Therefore,
will be the answer.
Decay once per year over a period of t years,
f(t) = ![(1-\frac{r}{1})^t](https://tex.z-dn.net/?f=%281-%5Cfrac%7Br%7D%7B1%7D%29%5Et)
=
Therefore,
will be the answer.