Which of the following equations are equivalent? Select three options.
2 answers:
You might be interested in
Answer:
(4,1)
Step-by-step explanation:
The vertex of the quadratic can be found using -b/2a. The vertex is the point (-b/2a, f(-b/2a)).
To find the x coordinate of the quadratic, define its a,b, and c. The quadratic has a = 2, b=-16, and c=31. Then -b/2a is -(-16)/2(2) = 16/4 = 4.
To find the y-coordinate, input the x=4 and solve for y.
The vertex is (4,1).
Answer:
f(x) = -2/3x - 3
Step-by-step explanation:
Given the values f(3) = - 1 and f(6) = 1
We're essentially provided (3, -1) and (6, 1).
Let (x1, y1) = (3, -1)
(x2, y2) = (6, 1)
Substitute these values into the slope formula:
m = (y2 - y1)/(x2 - x1)
m = [1 - (-1)]/(6 - 3)
m = (1 + 1) / 3
m = 2/3
Next, we need to find the y-intercept. Use one of the points, (6, 1), and the slope, m = 2/3, and substitute these values into the slope-intercept form to solve for the y-intercept, b:
y = mx + b
1 = 4 + b
Subtract 4 from both sides to solve for b:
1 - 4 = 4 - 4 + b
-3 = b
Therefore, the linear function is: f(x) = -2/3x - 3