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viktelen [127]
3 years ago
6

The product o 4z and 0 is

Mathematics
1 answer:
Kamila [148]3 years ago
8 0
The Government 45 is the first to graduate from school
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Which relation is a function?
Step2247 [10]
{(2, 3), (1, 5), (2, 7)} - NOT because 2->3 and 2->7
{(11, 9), (11, 5), (9, 3)} - NOT because 11->9 and 11->5
{(3, 8), (0, 8), (3, -2)} - NOT because 3->8 and 3->-2

{(-1, 5), (-2, 6), (-3, 7)} - YES
4 0
3 years ago
Find an expression (where you have to multiply polynomials) to represent the shaded region of #33 and if you could also include
Brrunno [24]
First, find the area of the circle using the formula A=pi r^2. 
A=pi (2x+3)^2 = pi(4x^2 + 12x + 9) 
Second, find the area of the rectangle inside by multiplying the polynomials. 
(X+1)*(3x+2) = 3x^2 + 5x +2 
Third, subtract the area of the rectangle from the area of the circle to find the area of the shaded region. 
pi(4x^2 + 12x + 9) - 3x^2 + 5x +2 =area of shaded region 
Or 
(pi (2x+3)^2) - ((X+1)(3x+2)) = area of shaded region


4 0
3 years ago
Roberta needs ribbon for a craft project. The ribbon sells for $3.74 per yard. Find the cost, in dollars, for 48 inches of the r
almond37 [142]
You have to convert 1 yard to 36 inches. so you do 3.74×3.74(1/3) because the extra 12 inches is one third of a yard. You eventually get 4.986 which rounds to 4.99
5 0
3 years ago
Suppose that the terminal side of angle alphaα lies in Quadrant I and the terminal side of angle betaβ lies in Quadrant IV. If s
melamori03 [73]

Solution :

It is given that :

$\alpha$ lies in the first quadrant.

And $\beta$ lies in the fourth quadrant.

Since, $\sin \alpha = \frac{5}{13}$     and $\cos \beta = \frac{6}{\sqrt{85}}$    (given)

$\sin \alpha = \frac{5}{13}$  

$\cos \alpha = \sqrt{1-\sin^2 \alpha}$

   $\cos \alpha = \frac{12}{13}$

Similarly  $\cos \beta = \frac{6}{\sqrt{85}}$

$\sin \beta = \sqrt{1-\cos^2 \beta}$

$\sin \beta = \sqrt{1-\frac{36}{85}}$

     $-\frac{7}{\sqrt{85}}$      (IVth quadrant)

Therefore,

$\cos (\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta$

                 $=\frac{12}{13}\times \frac{6}{\sqrt{85}}-\frac{5}{13}\times \frac{-7}{\sqrt{85}}$

                $= \frac{107}{13 \sqrt{85}}$

6 0
3 years ago
What percent of 50 is 18?<br> Enter your answer in the box.
Assoli18 [71]

Answer:36%

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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