Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
Answer:
it costs $17.7
Step-by-step explanation:
1.35/9 is 0.15
0.15 * 118 = 17.7
Answer:
y = 8x
Step-by-step explanation:
When the number of people increased by 10, the caterer charged an additional $80. Therefore, we estimate that the cost per person is $8. In order to verify:
$8/person * 15 people = $120. True. $8/person * 25 people = $200. True.
Therefore, if we let x represent the number of people being cater for and y represent the cost, the equation to model the situation is simply y = 8x.
hope it helps!
Answer:
same i feel bad but im here too
Answer: -8 is the answer.
Step-by-step explanation:
according to the question:
{{(8+4)*5}/(-10)}-2
= {[12*5}/(-10)]-2
= [60/(-10)]-2
= -6-2 = -8
