Answer:
The volume is increasing at a rate of 16286 in³/min.
Step-by-step explanation:
a) The volume of a cone is given by:
Where:
r: is the radius
h: is the height
The rate of change of the volume can be calculated by using the chain rule:
![\frac{dV}{dt} = \frac{\pi}{3}[\frac{dh}{dt}r^{2} + h\frac{d(r^{2})}{dt}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cfrac%7B%5Cpi%7D%7B3%7D%5B%5Cfrac%7Bdh%7D%7Bdt%7Dr%5E%7B2%7D%20%2B%20h%5Cfrac%7Bd%28r%5E%7B2%7D%29%7D%7Bdt%7D%5D%20)
Since h = 4/3 r we have:
![\frac{dV}{dt} = \frac{\pi}{3}[\frac{d(\frac{4r}{3})}{dt}r^{2} + \frac{4r}{3}\frac{d(r^{2})}{dt}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cfrac%7B%5Cpi%7D%7B3%7D%5B%5Cfrac%7Bd%28%5Cfrac%7B4r%7D%7B3%7D%29%7D%7Bdt%7Dr%5E%7B2%7D%20%2B%20%5Cfrac%7B4r%7D%7B3%7D%5Cfrac%7Bd%28r%5E%7B2%7D%29%7D%7Bdt%7D%5D%20)
![\frac{dV}{dt} = \frac{4\pi}{9}[\frac{dr}{dt}r^{2} + r\frac{d(r^{2})}{dt}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%5B%5Cfrac%7Bdr%7D%7Bdt%7Dr%5E%7B2%7D%20%2B%20r%5Cfrac%7Bd%28r%5E%7B2%7D%29%7D%7Bdt%7D%5D%20)
![\frac{dV}{dt} = \frac{4\pi}{9}[\frac{dr}{dt}r^{2} + 2r^{2}\frac{dr}{dt}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%5B%5Cfrac%7Bdr%7D%7Bdt%7Dr%5E%7B2%7D%20%2B%202r%5E%7B2%7D%5Cfrac%7Bdr%7D%7Bdt%7D%5D%20)
(1)
With:
= 3 in/min
And by entering the above values into equation (1) we have:
![\frac{dV}{dt} = \frac{4\pi}{9}[(3 in/min)*(36 in)^{2} + 2*(36 in)^{2}*3 in/min]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cfrac%7B4%5Cpi%7D%7B9%7D%5B%283%20in%2Fmin%29%2A%2836%20in%29%5E%7B2%7D%20%2B%202%2A%2836%20in%29%5E%7B2%7D%2A3%20in%2Fmin%5D%20)
Therefore, the volume is increasing at a rate of 16286 in³/min.
I hope it helps you!
8x - 4 = 6x - 10
8x - 6x = - 10 + 4
2x = -6
x = -3
3x = -9
Answer:
(e^3 / e^2n)
Step-by-step explanation:
Answer:
Relative frequency of selecting a 2 = 8/50 = 0.16
Relative frequency of selecting a 3 = 14/50 = 0.28
Step-by-step explanation:
When we have a given experiment with given outcomes (such that each time that we perform the experiment, one outcome happens) the relative frequency of a given outcome is the quotient between the number of times that that outcome happened, and the total number of times that the experiment was performed.
Here the experiment is selecting a random number between 1 and 5, and it is performed 50 times.
Out of these 50 times, the outcome "2" appears 8 times.
Then the relative frequency of selecting the number 2 is:
f(2) = 8/50 = 0.16
And of these 50 experiments, the outcome "3" appears 14 times.
Then the relative frequency of selecting the number 3 is:
f(3) = 14/50 = 0.28
Answer:
$70,201.38
Step-by-step explanation:
To determine the principal amount, we can use the formula:
A = $200,000
r = 7% or 0.07
t = 15 years
n = 12
Now let's substitute our values.
So the principal needed to get 200,000 in 15 years is $70,201.38.
