Answer:
Sue takes 3.3 hours to kayak 11 miles & marty takes 3.5 hours on her horse
Step-by-step explanation:
Sue's kayaking path is the hypotenuse of a right triangle.
so we use a squared + b squared = c squared
10.5^2+3.2^2=c^2
110.25+10.24=c^2
120.49=c^2
10.9768=c
and then because it said to round to the nearest tenth that would be 11.0 miles.
She's going at an average speed of 3.3 mph
that means it takes her about .3 hours to do 1 mile
so it would take her 3.3 hours to go 11 miles
marty is going at an average speed of 7 mph
so she takes 0.14 hours to go 1 mile
0.14 x 25 = 2.5
Answer:
100
Step-by-step explanation:
They are the same.
Hope I helped!
The US to euros is 1: 0.7716,
The euros to Polish is 1:4.0518
0.77 4.05 0.77 1 0.77
----- / --------- = ------- x ---- = ------
1 1 1 4.05 4.05
(so for every 0.77 dollars it is 4.05 zolty.)
hope this helps
sorry if it is confusing
I think it would a minimum because its positive. and the vertex would be (-.77,4.55) the minimum is 4.55
Answer:
- (6-u)/(2+u)
- 8/(u+2) -1
- -u/(u+2) +6/(u+2)
Step-by-step explanation:
There are a few ways you can write the equivalent of this.
1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...
(-u+6)/(u+2)
Or, you can rearrange the terms so the leading coefficient is positive:
(6 -u)/(u +2)
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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.
-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)
or
8/(u+2) -1
Of course, anywhere along the chain of equal signs the expressions are equivalent.
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3) You can separate the numerator terms, expressing each over the denominator:
(-u +6)/(u+2) = -u/(u+2) +6/(u+2)
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4) You can also multiply numerator and denominator by some constant, say 3:
-(3u -18)/(3u +6)
You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:
(1+x^2)(6 -u)/((1+x^2)(u+2))