PLEASEEEEEEEE HELPPPPPP!!!!!

You have entered a pie baking contest. In the contest, you must make several pies for the judges to taste. You will make your fa

erastova [34]

Pooooooooooooooooooooooooooooooooooooooopy :p

3 0

3 years ago

What is the initial value of the function represented by this table?

lakkis [162]

Answer:

Option D. 5

Step-by-step explanation:

we know that

The initial value of the function is the y-intercept, so is the value of the function when the value of x is equal to zero

In this problem observing the table

For x=0

The value of y is equal to y=5

therefore

The initial value is 5

4 0

3 years ago

A child attempts to open a five-disc

adelina 88 [10]

Answer:

. In conclusion, people have to become aware of the dangerous impact fossil fuels have on a long term, and how important it is to shift slowiy to renewable energy resources. However, since the use of renewable energy is a rather new development, it carries the weight of critics and careful long term observation. COuntries have to show commitment to renewable energy and have to evaluate which energy resources are cost-effective and the best with regards to their circumstances The only hindrance of using more renewable energy resources in future could be the finances to install these technologles.

5 0

2 years ago

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given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago

A math test is worth 100 points and has 38 problems. Each problem is worth either 5 points or 2 points. How many problems of eac

Natasha_Volkova [10]

Let x be the number of 5 points question.
Let y be the number of 2 points question.

Total number of questions is 38
x + y = 38

Total points is 100
5x + 2y = 100

x + y = 38 ------------- (1)
5x + 2y = 100 ---------(2)

From (1):
x + y = 38
x = 38 - y -------------- sub into (2)
5(38 - y) + 2y = 100
190 - 5y + 2y = 100
3y = 90
y = 30 ------------------ sub into (1)
x + 30 = 38
x = 38 - 30
x = 8

There are 8 5-point questions and 30 2-point questions

5 0

3 years ago

Read 2 more answers