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kakasveta [241]
3 years ago
11

Please help! Will give brainiest to correct person!! No links please!

Mathematics
2 answers:
mina [271]3 years ago
8 0

Answer:

H=39.0625

Step-by-step explanation:

D=32in

R=1/2d=32/2=16

Volume of cylinder:pi r^2h

V=pir^2h

10000pi=16^2hpi

256h=10000

h=39.0625

yKpoI14uk [10]3 years ago
5 0

Answer:

39 inch

Step-by-step explanation:

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Can someone help me i need help pls pls pls pls
Semmy [17]

Answer:

\huge\boxed{Answer\hookleftarrow}

\frac{2}{3}  \times  \frac{7}{4}  \\  =  \frac{2 \times 7}{3 \times 4}  \\  =  \frac{14}{12}  \\  =  \frac{7}{6}

You'll get the answer as 7/6 which is equal to <u>1</u><u>.</u><u>1</u><u>6</u>. 2/3 is equal to <u>0.66</u>.

•°•  \frac{7}{6}  >  \frac{2}{3}

✐ So, the answer is ⇻ <u>greater</u><u> than 2/3</u><u>.</u>

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

6 0
3 years ago
Please! Help! The table below shows preferences of dancing or playing sports for male and female students:
Kryger [21]

Answer:

D)   He calculated the joint relative frequency of female students who prefer playing sports. The conditional relative frequency for female students who prefer playing sports is 34%.

Step-by-step explanation:

The table is given as:

                          Playing sports Dancing     Row totals

Male students           18                      16              34

Female students       18                      35             53

Column totals  36                       51               87

  • We know that the joint relative frequency of an outcome is calculated as dividing the frequency of the outcome by the grand total.

Hence, when we divide the frequency of the female students who prefer playing sports i.e. 18 by the grand total i.e. 87 ; we obtain:

18/87=0.20689

which is approximately equal to 21%.

  • Hence, in order to calculate the conditional relative frequencies she should have divided the required frequency by the row total;.

     Hence, here we divide the  frequency of the female students who prefer playing sports i.e. 18 by the row total i.e. 53 ; we obtain:

18/53-0.3396

which is approximately equal to 34%.

Hence, option: D is correct.

5 0
3 years ago
Read 2 more answers
See attachment to help please. Trying to understand
Vaselesa [24]
It will be the last one since it is the one that makes more sense.
5 0
3 years ago
Please help
MrRa [10]

Answer:

About 99.7% of births would be expected to occur within 51 days of the mean pregnancy​ length

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Standard deviation = 17.

About what percentage of births would be expected to occur within 51 days of the mean pregnancy​ length?

51/17 = 3.

So, within 3 standard deviations of the mean.

About 99.7% of births would be expected to occur within 51 days of the mean pregnancy​ length

4 0
3 years ago
Help me or I ask 911​
OLga [1]
I think it’s B
So sorry if it’s wrong
Recommend a show for you to watch it’s criminal minds
3 0
3 years ago
Read 2 more answers
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