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Burka [1]
2 years ago
10

Please help its easy just i'm dvmb, just need this for my homework real soon!.. DON'T MIND THOSE ANSWERS SELECTED!!!!

Mathematics
1 answer:
trasher [3.6K]2 years ago
8 0
<h3><em>Hey there today we will solve your problem,</em></h3>

Number 1

_______________

<h3>Definitions</h3>
  • Vertical angles - <em>either of two angles lying on opposite sides of two intersecting lines.</em>

<em />

  • Linear Pair - <em>A linear pair is a pair of adjacent angles formed when two lines intersect.</em>

_______________

Now we can solve Number 1, there is one pair of Vertical angles being ∠5 and ∠3

_______________

Number 2

Since we know the definition of a Linear Pair we can solve this problem also, the only Linear Pair that we can choose out the ones give to us is ∠4 and ∠3, because they are adjacent.

_______________

{\huge{\boxed{\mathfrak{Answer}}}

  1. ∠5 and ∠3

    2. ∠4 and ∠3

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Help show work due asap​
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3 years ago
If the length of AB is 10 cm from the center and has a length of 12, find the approximate length from the center to CD.​
Lynna [10]

<u>Given</u>–

AB = 12 Cm

CD = 14 Cm

PO = 10 Cm

AP = 1/2 × 12 = 6 Cm

<u>Construction</u>–

Draw NO such that it is the perpendicular bisector of CB.

Hence,

ND = 1/2 × 14 = 7 Cm

To Find,

Measure of NO

<u>Solution</u>,

Here, PO Perpendicular to AB

Hence, APO is a right-angled triangle–

AO² = PO² + AP²

Or, AO² = 10 ² + 6 ²

Or, AO² = 36 + 100

Or, AO = √136 Cm

Or, AO = 11.66 Cm

Also, AO = OD = 11.66 Cm

( Radius of the same circle )

Now, in triangle OND,

OD² = ON² + ND ²

Or, 11.66 ² = ON² + 7²

Or, 136 = ON² + 49

Or, ON ² = 136 – 49

Or, ON ² = 87

Or, ON ² = √87

Or, ON = 9.3 Cm

Therefore, the appropriate length from center to CD is 9.3 Cm.

4 0
3 years ago
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