Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere
The differential of V with respect to r is:
dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
Here’s an explanation! let me know if you need further clarification
We have an inscribed angle here. Angle YXZ is an inscribed angle.
Angle YXZ can also be expressed as simply angle x but I will use angle YXZ.
Angle YXZ = (1/2)(arc YZ)
Angle YXZ = (1/2)(144°)
Angle YXZ = 72°
Done!
2) 4 = 90
5 = 45
6 = 45
16) this one's a bit long :)
PLEASE READ
I MADE A DUMB MISTAKE WHEN WORKING OUT THE HEIGHT
ITS NOT 8.41 ITS 9
SORRY ABOUT THAT
The chace of the number that will be pulled out of the hat being an even number is a 7 / 15 chance.
