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2 years ago

If the slope of a proportional relationship is 3, what is the equation that represents that line?

Mathematics

1 answer:

adelina 88 [10]2 years ago

5 0

Answer:

y = 3x

Step-by-step explanation:

A proportional function has the equation

y = kx, where k is the constant of proportionality and also the slope of the line.

Answer: y = 3x

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Use the Venn diagram to calculate probabilities. Circles A and B overlap. Circle A contains 15, circle B contains 10, and the in

grin007 [14]

Answer:

$(B) P(B)=\dfrac{16}{31}$

Step-by-step explanation:

From the Venn diagram, n(AUB)=31

The given probabilities in the option are calculated below:

$P(A)=\dfrac{21}{31}\\\\P(B)=\dfrac{16}{31}\\\\P(A|B)=\dfrac{P(A\cap B)}{P(B)}= \dfrac{6/31}{16/31} =\dfrac{6}{16}=\dfrac{3}{8} \\\\P(B|A)=\dfrac{P(B\cap A)}{P(A)}= \dfrac{6/31}{21/31} =\dfrac{6}{21}=\dfrac{3}{7}$

The only correct option is the probability of B which is $\frac{16}{31}$

8 0

3 years ago

Please help asap algebra 1

damaskus [11]

Answer:

Step-by-step explanation:

7+7+3= 17

8 0

3 years ago

Read 2 more answers

What shows the greatest common factor of 18 and 24 with 18/24 in simplest form

Monica [59]

Divide them both by 6

So it should be : 3/4

5 0

3 years ago

Read 2 more answers

What is the slope of the line with an equation of 5x + 8y = 16?<br> -8/5<br> -5/8<br> 5/8<br> 8/5

zzz [600]

Answer:

Slope m = -5/8

Step-by-step explanation:

5x + 8y = 16

Making y as subject of formula

8y = -5x + 16

Dividing each term by 8

8y/8 = -5x/8 + 16/8

y = -5x/8 + 2

Comparing with y = mx + c

Where m = slope and c the y intercept

Slope m = -5/8

5 0

2 years ago

In Which Quadrant is this true

34kurt

Given:

$\sin \theta$

$\tan \theta$

To find:

The quadrant in which $\theta$ lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only $\sin\theta$ and $\csc\theta$ are positive.

In Quadrant III, only $\tan\theta$ and $\cot\theta$ are positive.

In Quadrant IV, only $\cos\theta$ and $\sec\theta$ are positive.

We have,

$\sin \theta$

$\tan \theta$

Here, $\sin\theta$ is negative and $\tan\theta$ is also negative. It is possible, if $\theta$ lies in the Quadrant IV.

Therefore, the correct option is D.

5 0

3 years ago