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svetoff [14.1K]
3 years ago
10

If the slope of a proportional relationship is 3, what is the equation that represents that line?

Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

y = 3x

Step-by-step explanation:

A proportional function has the equation

y = kx, where k is the constant of proportionality and also the slope of the line.

Answer: y = 3x

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Determine the function
zalisa [80]

For each increment in x, the output is multiplied by 2. The function could be written the way a geometric sequence can be written:

... f(x) = 5·2^(x-1)

Or, it could be simplified to ...

... f(x) = (5/2)·2^x

The first 5 terms will be

... 5, 10, 20, 40, 80

5 0
3 years ago
Plz help I have no idea how to answer it​
saveliy_v [14]

5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0    and      x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0   then  p = -4m   and q = 3m²

3p² = 3(-4m)²               16q = 16(3m²)

      = 3(16m²)                      = 48m²

      = 48m²

3p² = 48m² = 16q     ⇒           3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

  • Bigger non-shaded Δ: L = 12-x, w = 10  ⇒ A = \dfrac{10(12-x)}{2}
  • Smaller non-shaded Δ: L = x, w = x ⇒ A=\dfrac{x(x)}{2}

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}

Area of ΔBEF:

\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18

5 0
3 years ago
PLEASE HELP
Rudiy27
Y= 3x-7
Is a linear unction
7 0
3 years ago
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9/10 times a number plus 6 is 51
goldenfox [79]
9/10n + 6 = 51
9/10n = 51 - 6
9/10n = 45
n = 45 * 10/9
n = 450/9
n = 50
5 0
3 years ago
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A seafood restaurant claims an increase of $1,750.00 over its average profit during a week where it introduced a special of bake
Juliette [100K]
Hello! I can help you with this! There are 7 days in 1 week. For these questions, we’re gonna have to do some division and a bit of multiplication.

a. 1,750 is the amount gained over 1 week. Let’s divide. 1,750/7 is 250. If that is true, then the seafood restaurant received $250 of extra profit each day.

b. This is the loss of $150 per day. To find the answer to this problem, all you have to do is 150 * 7. When you do that, you get 1,050. The restaurant would’ve lost $1,050 for the week.

c. This is the lost of $490 in one week. Again, to find the answer to this, divide. 490/7 = 70. The average daily change was $70.
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4 years ago
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