Answer:
a) The rate of change of the brightness after t days is
b) The rate of increase after one day is of 0.0915.
Step-by-step explanation:
The brightness after t days is given by:
A) Find the rate of change of the brightness after t days.
This is
The derivative of a constant is 0, the derivative of is
So, in this case, we have that:
The rate of change of the brightness after t days is
B) Find the rate of increase after one day.
This is . So
The rate of increase after one day is of 0.0915.
Answer:
x = 14.7
Step-by-step explanation:
Using the sine rule
Substitute the given values.
Rearrange the equation to get x on it's own.
x = 14.72246211
x = 14.7 (1dp)
Answer:
True
Step-by-step explanation:
This is true for a>0 and x>0. We can prove it by plugging in a and x for f(x) = ln(x)
f(ax) = ln(ax) = ln(a) + ln(x)
We see that ln(a) + ln(x) is exactly f(a) + f(x)
Therefore, the statement above is true for any a>0 and x>0
Answer:
<h2>The third graph</h2>
Step-by-step explanation:
|a| = a for a ≥ 0
|a| = -a for a < 0
therefore
|3| = 3 and |-3| = -(-3) = 3
Im down whats the question