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monitta
3 years ago
12

Suppose your average, after taking 4 quizzes, is 71 (out of 100). what must your average be on the next 5 quizzes to increase yo

ur average to 86 out of 100?
Mathematics
1 answer:
Anton [14]3 years ago
5 0
Short answer: 98
Remark

when you have an average of 71, it's like saying that you took 4 quizzes and got 71 on all of them. 
Step One
Find the total point count for the 4 quizzes.
T_4 = 71 * 4 = 284

Step Two
Create an equation that will give you the necessary point count to average 86.

284 + 5*x = 86 * 9
Why did we do this? It is because you have 9 quizzes altogether. All nine must be something that gives a point count of 86 on each quiz.  You have to put together 9 such quizzes with a total count of 774.

Step three 
Solve the equation.
284 + 5x = 774  Subtract 284 from both sides.
5x = 774 - 284
5x = 490   Divide by 5
x = 490/5
x = 98

You must get an average of 98 on the next 5 quizzes

Answer: 98 <<<<<

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Step-by-step explanation:

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Weight 0 means a string with no occurrence of 1

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Hence, the number of string with weight 6

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Explanation

n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

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Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

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6C5 = 6

Hence, the number of string with weight 5 is 6

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n = 6 and r = 6

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Weight of 7 means that a string that has 7 occurrence of 1

The total length of a 6 bit is 6

Since 6 is less than 7, there's no way a bit of weight 7 can occur.

So, the right answer for this is 0.

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