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Nezavi [6.7K]
2 years ago
10

PLEASE ANSWER ILL GIVE YOU BRIANLIEST

Mathematics
2 answers:
GREYUIT [131]2 years ago
6 0

Answer:

I Think It's 523.6 I don't know Tho

Step-by-step explanation:

cluponka [151]2 years ago
4 0

Answer:

Answer is 523.6

Step-by-step explanation:

I'm not 100% sure but:

Volume = 4/3 πr^3

= 4/3 × π × 5^3

= 523.598

The radius is 5 meaning the volume would be about 523.6.

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Help me I need an answer today!!!!!!!
krek1111 [17]
The rate of change is 25 because it goes 25 50 75 100 think of it like quarters
4 0
2 years ago
Please help!!!!!!!!!!!!!!!! 100pts,
Helga [31]

QUESTION:

The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.

ANSWER:

Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–

  • P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.

Since there are 10 digits to choose from, we can assume that n = 10.

Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.

Now, plug these values into the formula and solve:

= 10!(10−5)!

= 10!5!

= 10⋅9⋅8⋅7⋅6

= 30240.

3 0
2 years ago
When an automobile is stopped with a roving safety patrol,each tire is checked for tire wear, and each headlight is checkedto se
ryzh [129]

Answer:

a) Joint ptobability distribution

\begin{pmatrix}  &Y=0&Y=1&Y=2&Y=3&Y=4\\X=0&0.3&0.05&0.025&0.025&0.1\\ X=1&0.18&0.03&0.015&0.015&0.06 \\ X=2&0.12&0.02&0.01&0.01&0.04\end{pmatrix}

b) P(X<= 1 and Y <= 1) = P(X<= 1) * P(Y<=1) = 0.56

c) P(X + Y = 0)=0.3

d) P(X + Y <= 1)=0.53

Step-by-step explanation:

We have to construct the joint probability table with the marginal probabilities of X and Y.

X can take values from 0 to 2, and Y can take values from 0 to 4.

We can calculate each point of the joint probability as:

P(x,y)=P_x(x)*P_y(y)

Then, the joint probabilities are:

X=0 Y=0 Px=0.5 Px=0.6 P(0,0)=0.3

X=0 Y=1 Px=0.5 Px=0.1 P(0,1)=0.05

X=0 Y=2 Px=0.5 Px=0.05 P(0,2)=0.025

X=0 Y=3 Px=0.5 Px=0.05 P(0,3)=0.025

X=0 Y=4 Px=0.5 Px=0.2 P(0,4)=0.1

X=1 Y=0 Px=0.3 Px=0.6 P(1,0)=0.18

X=1 Y=1 Px=0.3 Px=0.1 P(1,1)=0.03

X=1 Y=2 Px=0.3 Px=0.05 P(1,2)=0.015

X=1 Y=3 Px=0.3 Px=0.05 P(1,3)=0.015

X=1 Y=4 Px=0.3 Px=0.2 P(1,4)=0.06

X=2 Y=0 Px=0.2 Px=0.6 P(2,0)=0.12

X=2 Y=1 Px=0.2 Px=0.1 P(2,1)=0.02

X=2 Y=2 Px=0.2 Px=0.05 P(2,2)=0.01

X=2 Y=3 Px=0.2 Px=0.05 P(2,3)=0.01

X=2 Y=4 Px=0.2 Px=0.2 P(2,4)=0.04

We can write it in the form of a matrix:

\begin{pmatrix}  &Y=0&Y=1&Y=2&Y=3&Y=4\\X=0&0.3&0.05&0.025&0.025&0.1\\ X=1&0.18&0.03&0.015&0.015&0.06 \\ X=2&0.12&0.02&0.01&0.01&0.04\end{pmatrix}

b) From the joint probability P(X<= 1 and Y <= 1) is equal to

P(X\leq 1 \& Y \leq 1)=P(0,0)+P(0,1)+P(1,0)+P(1,1)\\\\P(X\leq 1 \& Y \leq 1)=0.3+0.05+0.18+0.03=0.56

We can calculate P(X<= 1) * P(Y<=1)

P_x(X\leq 1)=P_x(0)+P_x(1)=0.5+0.3=0.8\\\\P_y(Y\leq1)=P_y(0)+P_y(1)=0.6+0.1=0.7\\\\P_x(X\leq1)*P_y(Y\leq1)=0.8*0.7=0.56

Both calculations give the same result.

c) Probability of no violations

P(X+Y=0)=P(0,0)=0.3

d) P(X + Y <= 1)

P(X+Y \leq 1)=P(0,0)+P(0,1)+P(1,0)\\\\P(X+Y \leq 1)=0.3+0.05+0.18=0.53

5 0
3 years ago
Solve -(1+7g)-6(-7-g)=36
maria [59]

Eliminate parentheses using the distributive property.

... -1 -7g +42 +6g = 36

... 41 -g = 36 . . . . collect terms

... 41 -36 = g . . . . add g-36 to both sides

... 5 = g . . . . . .. . . your answer

6 0
3 years ago
18. One month, the Taylor family had cash receipts of $876.16. Their excess of cash receipts above cash payments was $56.14. Wha
Valentin [98]

$820.02

Step-by-step explanation:

Since the Taylor family had cash receipts of $876.16 and their excess of cash receipts above cash payments was $56.14.

The total cash payments for the month will be calculated as:

= $876.16 - $56.14

= $820.02

6 0
2 years ago
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