Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
The number is 70
Step-by-step explanation:
Is means equals and of means multiply
91 = 130% *W
Changing to a decimal form
91 = 1.3W
Divide each side by 1.3
91/1.3 = 1.3 W/1.3
70 = W
Answer:
Step-by-step explanation:
(X^2+y^2)^2 polynomial identify. Simplify
i.e
Solution:
We have the identity,
In the Question
Substituting in the identity we get
Also we have
Which is the required
Answer:
5/6
Step-by-step explanation:
Only 5 is not divisible by 12
