Answer:
2
Step-by-step explanation:
We are to determine the value of KM which is adjacent to angle 35. we also have the value for the hypotenuse. Thus we would use COS
Cos 35 = adjacent /hypotenuse
0.8192 = adjacent / 123
adjacent = 0.8192 x 123 = 100.7557 cm
100.8 cm
the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero
Answer:
320 in.²
Step-by-step explanation:
Let's think of the shape as a normal rectangle with a height of 16 inches. Now all we need is the length. If you look at the right corner, it looks like a piece has been cut out. Since that piece has the same length and height of 8 inches, it is a square. This tells us the missing length of the entire length of the rectangle. Now the length of the rectangle is 16 inches + 8 inches, which is 24 inches.
The total area of the rectangle is 16 × 24, which is 384.
Then from the total area, we just need to subtract the area of the cut-out part. The area of the cut-out square is 8 × 8, which is 64.
384 - 64 = 320
The total surface area of the following complex shape is 320 in.²
Answer:20
Step-by-step explanation:
25% is 1/4 so multiply 5 times 4
Answer: i got 44 for the answer
Answer:
Depth of the rain gutter is 8 inches
Step-by-step explanation:
Let’s assume ‘x’ is the depth of the rain gutter
Then the width of the rain gutter can be written as 16 - 2x
Cross sectional area
A = depth x width
Substitute values
A = x*(16 - 2x)
A = 16x – 2x^2
Now according to axis of symmetry for maximum area x = -b/2a
x = -16/2*(-2)
x = 4 inches depth of rain gutter, substitute the value of x to get
Width of rain gutter 16 – 2(4) = 8 inches
Area of the rain gutter for maximum water flow
A = 4 * 8
A = 32 square inch.
