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3 years ago

Help ASAP Answer only if you know if you put links I will report

Mathematics

1 answer:

juin [17]3 years ago

5 0

Answer: It is a reflection over the x axis!

Step-by-step explanation: The x axis is the horizontal line, so you reflect it over there. It is a reflection because you didn't rotate it, and you didn't translate it. You reflected the coordinates to the other side.

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Find the inverse of f(x) = 2

allochka39001 [22]

Answer:

the inverse is option B.............

3 0

3 years ago

Identify the solution to the system of equations {x=-2y-6 -3x-7y=18

Gemiola [76]

Answer:

(- 6, 0 )

Step-by-step explanation:

x = -2y - 6 → (1)

- 3x - 7y = 18 → (2)

substitute x = - 2y - 6 into (2)

- 3(- 2y - 6) - 7y = 18 ← distribute parenthesis and simplify left side

6y + 18 - 7y = 18

- y + 18 = 18 ( subtract 18 from both sides )

- y = 0 , then

y = 0

substitute y = 0 into (1)

x = - 2(0) - 6 = 0 - 6 = - 6

solution is (- 6, 0 )

7 0

3 years ago

Read 2 more answers

PLEASE HELP, VERY URGENT!!!!

nirvana33 [79]

Answer:

Y=-2X + 4

Step-by-step explanation:

Follow the rise of run and to get the B= 4 you must answer this problem

Y+2=-2(X-3)

3 0

3 years ago

Plz help..................refresh page before u answer

S_A_V [24]

$\dfrac{7}{x^2-36}-\dfrac{1}{x-6}=\dfrac{7}{(x+6)(x-6)}-\dfrac{1}{x-6}=\\\\\\=
\dfrac{7}{(x+6)(x-6)}-\dfrac{(x+6)}{(x+6)(x-6)}=\dfrac{7-x-6}{(x+6)(x-6)}=\boxed{\dfrac{1-x}{(x+6)(x-6)}}$

Answer B.

8 0

3 years ago

Write the equation of the line that passes through the two points: (-4, 11) and (2,-4)

snow_tiger [21]

Answer:

y= - $\frac{5}{2}$ x+1

Step-by-step explanation:

Utilize the formula of $\frac{y2-y1}{x2-x1}$ to find the distance between two points, or in this case, the equation of the line that passes through two points.

Applying the given points to identify the slope

1. Plug the coordinates into the y and x values. $\frac{-4-11}{2+4}$ =- $\frac{15}{6}$ .

1.5. Simplify; divide both the numerator and the denominator by 3. - $\frac{5}{2}$ .

Applying slope and a point to find the y-intercept of the equation of a line

1. Utilize the formula of y=mx. Though this sounds strange, morph the sign of equality into subtraction.

1.5. Result: y-mx

2. Do this for both points.

First point: (-4,11)

y-mx

11 + $\frac{5}{2}$ (-4)

11 + -10 (11-10)

Plug the result and the slope into y=mx+b to find the slope of the line.

Result: y=- $\frac{5}{2}$ x+1.

Check your answer to confirm that the value of y is true for both points

1. Do the same thing you did with the first point, but use the second point this time.

y-mx

-4 + $\frac{5}{2}$ (2)

-4 + 5

Plug the result and the slope into y=mx+b to find the slope of the line.

Result: y=- $\frac{5}{2}$ x+1. Identical to point one's result.

In conclusion, both of the results are the same. Therefore, the equation of the line must be y=- $\frac{5}{2}$ x+1.

3 0

4 years ago