Answer:
The reaction rate of the digestion helps in understanding which part of the digestive system having trouble in digestion especialy stomach and intenstine related.
It involves the fact that most of the enrgy or calories are get by the small intestine and also vitamins and minerals are absorbed by this part of the digestive system so if the small intestine is having problem the rate of digestion would be affected and and an individual could be malabosrbed.
If the problem lies in the stomach it might show some effects of a poor digestion, however the rate of digestion would be better than if the problem lies in the small intestine.
B- speed up the chemical reaction
Answer:
The red color of the colonies is an example of <u>a phenotype .</u>
Explanation:
Serratia marcescens -
They are the species ,that are , gram - negative bacteria , rod - shaped ,
they are from the family of Enterobacteriaceae .
Serratia marcescens are mostly found in the urinary and respiratory tracts of the hospitalized adults and in children , in the gastrointestinal systems .
S. Mercescens are most commonly found in the environment , growing the bathroom and dirt .
It is gram-negative, produces a reddish - orange tripyrrole pigment called the prodigiosin , is an example of phenotype .
Answer:
5.) The possible genotypes should be: RR RB BB ( if the could for the same proteins)
6.) Frequency of R: 0.5
7.)Frequency of R: 0.5
8.)Frequency of R: 0.375
Explanation:
5.) If R and B code for the different forms of the same protein then they are only a few possible out comes
6.) First calculate the total alleles in population
allele R= 40
Allele B=40
total allele = R+B= 40+40
=80
Now to find allele R frequency is:
(Total R alleles) / (Total allele in pop)
40/80=
0.5
7.)Calculate the total alleles
Alleles from for R
RR= 10
R=10x 2= 20
Multiply the value by 2 because there are 2 R alleles present in
RB=20
R=20
Number doesn't change there is only 1 R allele
Total R=20+20
=40
Alleles For B
BB=10
B=10×2
=20
Same thing here, two B alleles together so multiple by 2
RB=20
B=20
Total B= 20+20
=40
Total alleles in pop add
40+40
=80
Frequency of R
Total of R/Total Alleles
=40/80
=0.5
8.)Repeat the same thing in 7 but use different numbers
RR=10
R=10x2
=20
RB=10
R=10
Total R= 20+10
=30
