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Harlamova29_29 [7]
3 years ago
8

If a quadrilateral is a rhombus, then it is _______________________ *

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Step-by-step explanation:

parallelogram

If a quadrilateral is a rhombus, then it is a parallelogram. If a parallelogram is a rhombus, then its diagonals are perpendicular. If a parallelogram is a rhombus, then each diagonal bisects a pair of opposite angles.

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D(n) = -5 (1/2)n-1<br> What is the 3rd term in the sequence?
jonny [76]

Answer:

-5

Step-by-step explanation:

dₙ = -5 (1/2)n-1

the 3rd term in the sequence means n = 3

d₃ = -5(1/2)(3-1) = -5(1/2)(2) = -5

3 0
4 years ago
Read 2 more answers
Learning Task II. Illustrate the following: Illustration Given 1. Line Segment MN 2. Ray XY 3. Ray YX 4. Angle ABC 5. LK​
Mashutka [201]

The illustration of the given mathematical elements is as in the attached images.

<h3>Illustration of mathematical elements</h3>

For line segments;

  • The beginning and end of the line are specified by the assigned alphabets.

However, for rays;

  • The ray is illustrated to originate from a point and span on from there till infinity.

For angles;

  • The alphabet in the middle of the set of 3 alphabets used to identify the angle represents the center point of where the angle is located.

Read more on illustration of mathematical elements;

brainly.com/question/18430725

6 0
3 years ago
How would you find the vertices of an image of a figure was rotated 270 degrees clockwise? 15 POINTS! DESPERATE
boyakko [2]

Rotation Coordinate Notation About the Origin:

90–degree counterclockwise: (x, y) → (-y, x)

180–degree counterclockwise: (x, y) → (-x, -y)

270–degree counterclockwise: (x, y) → (y, -x)

Use this to help you..

Example -

The vertices of a triangle are

( 1 , 3 ) ( 3 , -4 ) , ( - 6 , -8 )

270 degrees , clockwise , rotated from origin ( x , y ) - ( y , -x )

The first vertice = ( 1 , 3 )

after rotation - ( 3 , - 1 )

The second vertice = ( 3 , -4 )

After rotation - ( -4 , -3 )

The third vertice = ( -6 , - 8 )

After rotation - ( -8 , 6 )

Hope my answer helps!

5 0
4 years ago
Read 2 more answers
Given that f(x) =x^2-3/3<br> a) Find f(3)<br> b) Find f'(x)<br> c) Find f'(11)
Ber [7]
A) F(3)=3^2-3:3= 9-3:3=9-1=8
B) ?
C) F(11)= 11^2-3:3=121-1= 120

I think this
6 0
3 years ago
An explained answer
Sholpan [36]

Answer:

  225

Step-by-step explanation:

When you fill in values of n, you find the series is an arithmetic series of 15 terms with a first term of 1 and a common difference of 2. The formula for the sum of such a series can be used.

<h3>Terms</h3>

Looking at terms of the series for different values of n, we find ...

  for n = 1: 2(1) -1 = 1 . . . . . the first term

  for n = 2: 2(2) -1 = 3 . . . . the second term; differs by 3-1=2

  for n = 15: 2(15) -1 = 29 . . . . the last of the 15 terms

<h3>Sum</h3>

The sum of the terms of an arithmetic series is the product of the average term and the number of terms. The average term is the average of the first and last terms.

  Sum = (1 +29)/2 × 15 . . . . . . average term × number of terms

  Sum = 15 × 15 = 225

The sum of the series is 225.

__

<em>Additional comment</em>

Based on the first term (a1), the common difference (d), and the number of terms (n), the sum can also be written ...

  S = (2×a1 +d(n -1))(n/2)

For the parameters of this series, the sum is ...

  S = (2(1) +2(15 -1))(15/2) = 30(15/2) = 225

5 0
2 years ago
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