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vlabodo [156]
3 years ago
10

HELP ASAP PLEASE!!!!

Mathematics
1 answer:
alexdok [17]3 years ago
8 0

Answer:

Here, AB = AC [ /_ B = /_ C ]

or, 9x - 11 = 7x -3

or, 9x - 7x = 11 -3

or, 2x = 8

or, x = 4

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Six more than five times a number (x) is at least twenty-one
I am Lyosha [343]
The answer to this would be 5x+6>=21. Just wanted points :P
3 0
3 years ago
Read the question on the picture.
Marizza181 [45]

These two lines are congruent (the same) so we can set them equal to each other and solve.

5x-4=3x+6

The first thing we need to do is subtract 3x from both sides leaving us with 2x-4=6

Now we can add 4 to both sides leaving us with 2x=2

Now we need to divide both sides by 2 to get x alone.

Giving us our final answer of x=1

3 0
3 years ago
Convert 27/20 to a decimal
Tatiana [17]
27/20

= 20/20 + 7/20

= 1 + 7/20

= 1.00 + 0.35

= 1.35

------

List of values to remember (extras):

0.05 = 1/20 = 5%
0.10 = 1/10 = 10%
0.15 = 3/20 = 15%
0.20 = 1/5 = 20%
0.25 = 1/4 = 25%
0.30 = 3/10 = 30%
0.35 = 7/20 = 35%
0.40 = 2/5 = 40%
0.45 = 9/20 = 45%
0.50 = 1/2 = 50%
0.55 = 11/20 = 55%
0.60 = 3/5 = 60%
0.65 = 13/20 = 65%
0.70 = 7/10 = 70%
0.75 = 3/4 = 75%
0.80 = 4/5 = 80%
0.85 = 17/20 = 85%
0.90 = 9/10 = 90%
0.95 = 19/20 = 95%
1.00 = 1 = 100%
8 0
3 years ago
Read 2 more answers
An instructor who taught two sections of engineering statistics last term, the first with 20 students and the second with 30, de
Lelechka [254]

Answer:

(a) P(X=10) = 0.2070

(b) P(X\geq 10) = 0.3798

Step-by-step explanation:

Note that in this problem we have an initial population N = 50, of which 30 fulfill a certain characteristic "m" (belong to the second section). Then, from the population N, a sample of size n = 15 is selected and it is desired to know how many comply with the desired characteristic (second section).

So

Let X be the number of projects in the second section, then X is a discrete random variable that can be modeled by a hypergeometric distribution.

(a)

Therefore, to answer question (a) we use the following equation presented in the attached image:

Where:

N = 50\\m = 30\\n = 15\\X = 10

Then:

P (X = 10) = \frac{\frac{30!}{10!(30-10)!}\frac{20!}{5!(20-5)!}}{\frac{50!}{15!(50-15)!}}\\\\\\P(X=10) = 0.2070

(b)

For part (b) we have:

P(X\geq10) = 1-P(X

P(X\geq 10) = 1-0.6202 \\\\P(X\geq 10) = 0.3798

4 0
3 years ago
Which statements are true about the fully simplified product of (b minus 2 c)(negative 3 b + c)? Select two options.
Ket [755]

Answer:

The simplified product, in standard form, has exactly 2 negative terms. The simplified product has 2 terms.

Step-by-step explanation:

(b-2c)(-3b+c)

distribute and you will get

-3b^2+bc+6bc-2c^2

combine like terms

-3b^2+7bc-2c^2

4 0
3 years ago
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