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masha68 [24]
3 years ago
6

Simplify 6x+(- 9)-9(5x+5)+x

Mathematics
2 answers:
Hatshy [7]3 years ago
4 0

Answer:

Step-by-step explanation:

I've already answered this question.

liq [111]3 years ago
3 0

Answer:

-38x-54

Step-by-step explanation:

6x+(-9)-9(5x+5)+x

6x-9-9(5x+5)+x

6x-9-45x-45+x

-38x-9-45

-38x-54

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2x squared plus 3x minus 2 plus 7
alex41 [277]

Answer:

2x^2 + 3x + - 2 + 7

4x + 3x - 2 + 7

7x + 5

Step-by-step explanation:

2x^2 + 3x + - 2 + 7

4x + 3x - 2 + 7

7x + 5

5 0
4 years ago
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Please help me i dont get this
MissTica

Answer:

Step-by-step explanation:

Since their both negatives, February should be the colder tempuerter.

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3 years ago
Find the Equivalent Ratio<br> 1/2 : 3/4 4 1/2 : x
zmey [24]
The answer will be
(27/16) hope this helps
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4 0
3 years ago
PLEASE ANSWER + BRAINLIEST!!
lora16 [44]
I'd like to see some of your own efforts here.  This is the third time you've posted two "factor completelyl" problems, without sharing what you've already done.

<span>3v^2 - 8v - 16 cannot be reduced.  Thus, your best choice to find roots is to apply the quadratic formula:

         8 plus or minus sqrt( 64-4(3)(-16) )
v = ---------------------------------------------------
                                2(3)
        8 plus or minus sqrt( 64 + 192 ) 
   = ---------------------------------------------
                                 6
         8 plus or minus sqrt(256)
    = -------------------------------------
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     = 8 + 16, all divided by 6, or    8 - 16, all divided by 6

     = 4 or -8/6, or 4 or -4/3.

The factors are (v-4) and (v + 4/3).</span>
6 0
4 years ago
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In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
ladessa [460]

Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets

n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )

where n\left ( N\cup E\right )=Students either nose or ear Pierced

n\left ( N\cap E\right )=no of students having both nose and ear pierced

40=7+36-n\left ( N\cap E\right )

n\left ( N\cap E\right )=43-40=3

3 0
4 years ago
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