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Fofino [41]
3 years ago
6

Shoshana has 5/6 foot of string. greg has 3/4 as much. shoshana multiplies 5/6 by 3/4 to find out has much greg has who has more

string
Mathematics
1 answer:
Reptile [31]3 years ago
8 0
Shoshana has more string than greg does.
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What is the equation of a line that passes through (.5,4.25) and (2,18.5) and has a y-intercept of -.5
nordsb [41]

Answer:

y=9.5x-.5 Y2 minus Y1 divided by X2 minus X1 gets you the slope

8 0
3 years ago
Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-
djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

A(x_{1}, y_{1}})=(-20, 25)

B(x_{2}, y_{2}})=(30, 25)

C(x_{3}, y_{3}})=(30, -10)

D(x_{4}, y_{4}})=(-20, -10)

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}

AB=\sqrt{(30+20)^{2}}

AB=\sqrt{(50)^{2}

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}

BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}

BC=\sqrt{(-35)^{2}}

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}

DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}

DC=\sqrt{(30+20)^{2}}

DC=\sqrt{(50)^{2}}

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}

AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}

AD=\sqrt{(-20+20)^{2}+(-35)^{2}}

AD=\sqrt{(-35)^{2}}

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0
3 years ago
If your car used 19.2 gallons of gas to go 1293.6 miles, how many miles per gallon (mpg) did the car get?
Anna007 [38]
G=m/x
G-gallons
m-miles
x-miles per gallon
19.2= 1293.6/x
x=1293.6/19.2
x= 67.375mpg
Therefore, the vehicle traveled 67.375 miles to 1 gallon
5 0
3 years ago
Good morning everyone :)​
Triss [41]

Answer:

Good Morning

:)

Step-by-step explanation:

5 0
2 years ago
Help me out hunnys ❤️
Alenkinab [10]

Answer:

g(x)=3(x+3)^2-8

Step-by-step explanation:

You can solve by using these acronyms.


H. orozontal.

I. nside.

O. pposite.


Meaning that a horozontal translation would be written inside the parenthesis and the poopsite sigh you would usually (Ex. Left is usually negitave but in this case it is positive).


The other acronym is,


V. erticle.

O. utside.

S. ame.


Meaning for a vrerticle translation the number would go on the outside of the parenthesis and tha sign would be normal (Ex. Negitave would be left and positive would be right).


For this one use H.I.O sinse you are moving on a horozontal plain. You are only working with the (x-2) nothing else matters.


Since you are moving left the number will move up 3 hence the O.


<h2><u>This transformation leaves you with g(x)=3(x+3)^2-8</u></h2>



3 0
3 years ago
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