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ruslelena [56]
3 years ago
5

during one stage of the drawbridge motion the raised end is 18 yards above the ground. what is the incline of the drawbridge to

the nearest hundredth
Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0

Answer:

helldfc ghhh44 787666$ 46

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Liz wants to make several batches of biscuits. She has 27 tablespoons of yeast left in the jar and each batch of biscuits takes
asambeis [7]

Answer:

8

Step-by-step explanation:

27 divided by 3 1/4 =

27 divided by 13/4=

27 times 4/13 = 108/13 = 8.307

At most she can make 8 taches.

8 0
2 years ago
Solve for x. -5x + 13 = -17
Lana71 [14]

Subtract 13 from both sides

-5x = -17 - 13

Simplify -17 - 13 to -30

-5x = -30

Divide both sides by -5

x = -30/-5

Two negatives make a positive

x = 30/5

Simplify 30/5 to 6

<u>x = 6</u>

7 0
3 years ago
Read 2 more answers
Find the area of the following figure:
stellarik [79]

Answer:

12m

Step-by-step explanation:

You can break this shape down into a square and a trapezoid. Frist you can find the area of the square by multiplying 2 by 5 to get 10. Then you would find the area of a trapezoid by doing Area = 1/2height(base1+base2). We can find the height by subtracting 5 from 9. (We do this because we know the side of the square is 5m) Therefore the height would be 4m. We know the bases are 2 and 4. From there you can plug those numbers in to the formula. Area=1/2 * 4 (2 + 4)

Area= 1/2 * 4 (6)

Area = 2(6)

Area = 12m

4 0
3 years ago
Does the (1,2) <br> satisfy the equation Y equals 3X
AlekseyPX
No. When you plug in x and y you get 2=3
8 0
3 years ago
Segment AB has endpoints on the coordinate grid where A is (- 18, 5) and B is (- 4, 5) Point Z is located exactly 1/8 of the dis
fenix001 [56]

Given:

Endpoints of segment AB are A(- 18, 5) and B(- 4, 5).

Point Z is located exactly 1/8 of the distance from A to B.

To find:

The value of the x-coordinate of point Z.

Solution:

Point Z is located exactly 1/8 of the distance from A to B.

AZ:AB=1:8

AZ:ZB = AZ:(AB-AZ)= 1:(8-1) = 1:7

It means point Z divided segment AB in 1:7.

Using section formula, the x coordinate of point Z is

x-coordinate=\dfrac{mx_2+nx_1}{m+n}

x-coordinate=\dfrac{1(-4)+7(-18)}{1+7}

x-coordinate=\dfrac{-4-126}{8}

x-coordinate=\dfrac{-130}{8}

x-coordinate=-16.25

Therefore, the required x-coordinate of point Z is -16.25.

3 0
3 years ago
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