Let f (x) = 2x - 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following: f (h(x)) and. g (f (x))

1 answer:

5 0

To get f(h(x)), we simply plug h(x) into the x value(s) of f(x), resulting in
2(x²+1)-1=2x²+2-1=2x²+1

For g(f(x)), we plug f(x) into the x value(s) of g(x), resulting in
3(2x-1)=6x-3

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