All categories

3 years ago

A set of data items is normally distributed with a mean of 240 and a standard deviation of 32. Convert 272 to a? z-score

Mathematics

1 answer:

dem82 [27]3 years ago

7 0

Answer:

z-score = 1

Step-by-step explanation:

Given

Mean= μ=240

SD= σ=32

In order to find the z-score of a value, the mean is subtracted from the value and then divided by standard deviation.

The formula for z-score is:

z-score=(x-μ)/σ

Here x is the value whose z-score is to be found.

In the given question, x = 272

So,

z-score=(272-240)/32

=32/32

So , the z-score for 272 is 1..

You might be interested in

5) According to the histogram, how many shipments were received that had at most 30 bulbs broken? A) 4 B) 5 C) 9 D) 13

MariettaO [177]

Answer:

The answer would be A) 4

6 0

2 years ago

A puzzle is shown below. what is the area of the shaded portions of the puzzle?

kolezko [41]

Answer:

it's a parallelogram

Step-by-step explanation:

May ot helpful

5 0

3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

Find(f+g)(x) for the following functions. f(x) = 12x2 + 7x + 2 g(x) = 9x + 7

Nimfa-mama [501]

Answer:

(f + g)(x) = 12x² + 16x + 9 ⇒ 3rd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- We can add and subtract two function by adding and subtracting their

like terms

Ex: If f(x) = 2x + 3 and g(x) = 5 - 7x, then

(f + g)(x) = 2x + 3 + 5 - 7x = 8 - 5x

(f - g)(x) = 2x + 3 - (5 - 7x) = 2x + 3 - 5 + 7x = 9x - 2

* Lets solve the problem

∵ f(x) = 12x² + 7x + 2

∵ g(x) = 9x + 7

- To find (f + g)(x) add their like terms

∴ (f + g)(x) = (12x² + 7x + 2) + (9x + 7)

∵ 7x and 9x are like terms

∵ 2 and 7 are like terms

∴ (f + g)(x) = 12x² + (7x + 9x) + (2 + 7)

∴ (f + g)(x) = 12x² + 16x + 9

* (f + g)(x) = 12x² + 16x + 9

8 0

3 years ago

Read 2 more answers

Ming writes a number pattern on a slip of paper and hands it to his friend Jack. 24 21 23 20 22 19 21 18 Jack writes the next nu

tiny-mole [99]

The rule is -3, then +2

24-3 = 21
21 + 2 = 23
23-3= 20
20+2= 22
22-3= 19
19+2 = 21
21-3= 18
18+2 = 20

3 0

3 years ago